更改shell中某行的内容

Question

我试图从命令行中获取包含名称的行号。 然后，我想用一个新名称来更改该名称。 然后打印新行。 我在这里：

echo -n "enter name" 
read name 
grep -n "$name" file 

它会返回例如3项

1)Sofia : 432-4567 
2) 
3) 
echo "Which line will be changed?" 
read number 

现在我想在第1行， 和打印与罗瑞改变索菲亚：

The new entry is Lorie : 432-4567 

Answer 1

尝试使用bash：

#!/usr/bin/env bash 

read -p "Enter name: " name 

grep -n "$name" file || { echo "'$name' not found in file." >&2; exit 1; } 

read -p "Which line do you want to change? " number 

# Note: You should check to make sure that a valid 
#  line number was entered. 

# Define variables containing the name to replace and its replacement. 
old=$name 
new='Lorie' 

# Use Sed to modify the line of interest in the input file. 
# A backup of the original file is saved as file.bak. 
# Note that, to avoid confusion, all literal parts of the Sed 
# script are maintained as *single*-quoted strings, with values from 
# shell variables *spliced in* (as variable references inside a *double*-quoted string). 
sed -i.bak "$number"' { s/^'"$old"' :/'"$new"' :/; }' file 

# Report the modified line. 
echo "The new entry is: $(sed -n "$number"' {p;q;}' file)" 

注意：如果你不希望要备份原文件，语法取决于你所使用的执行sed：

• GNU sed：sed -i ... # simply do not append a value to -i
• BSD sed，也使用OSX：sed -i '' ... # -i requires a separate, empty argument
• 如果您sed不支持-i干脆，用下面的习惯：
  • sed ... file > tmpfile && mv tmpfile file