PostgreSQL。创建嵌套的JSON对象

在我的Postgres的功能，我有一组JSON的：PostgreSQL。创建嵌套的JSON对象

{"layer_name":"rooms","properties":{"fillOpacity":1,"strokeColor":"#606576","strokeWidth":"3"}} 
{"layer_name":"map","properties":{"fillColor":"#3D404F"}}

我需要修改它的结构：

{ 
    "rooms": {"fillOpacity":1,"strokeColor":"#606576","strokeWidth":"3"}}, 
    "map: {"fillColor":"#3D404F"} 
}

我试图通过迭代设置并填写两个数组（一个键，其他VOR falues），所以我可以用json_object(keys text[], values text[])创建所需的JSON：

CREATE OR REPLACE FUNCTION appearance.get_styles(out response text) 
    RETURNS text 
AS 
$BODY$ 
    declare 
    vResult json; 
    i json; 
    keys TEXT[]; 
    vals TEXT[]; 
    layers json; 
begin 
    with a as (SELECT layer_name, properties FROM appearance.styles) 
    select json_agg(a) 
    into vResult 
    from a; 

    FOR i IN SELECT * FROM json_array_elements(vResult) 
    LOOP 
    RAISE NOTICE 'props %', i; 
    keys = array_append(keys, i->>'layer_name'); 
    vals = array_append(vals, i->>'properties'); 

    END LOOP; 
    layers = json_object(keys, vals); 
    RAISE NOTICE 'props %', layers; 

response := concat ('"layersStyles"', ':', coalesce(layers::text,'[]')); 
response := '{' || response || '}'; 

end; 
$BODY$ 
LANGUAGE plpgsql VOLATILE SECURITY DEFINER;

但问题是，我要投json为text，并在最后我得到逃出字符串值：

"map" : "{\"fillColor\":\"#3D404F\"}", "rooms" : "{\"fillOpacity\":1,\"strokeColor\":\"#606576\",\"strokeWidth\":\"3\"}"}

而且这不是我所需要的。我无法弄清楚如何制作嵌套的json对象。没有看到它的任何功能here。有更好的方法吗？

来源

2016-07-07 Lazarev Alexandr

在json_object_agg函数的帮助下求解。

CREATE OR REPLACE FUNCTION appearance.get_styles(out response text) 
    RETURNS text 
AS 
$BODY$ 
    declare 
    vResult json;  
begin 
    SELECT json_object_agg("layer_name", "properties") from appearance.styles 
    into vResult; 
    response := concat ('"layersStyles"', ':', coalesce(vResult::text,'[]')); 
    response := '{' || response || '}'; 

end; 
$BODY$ 
LANGUAGE plpgsql VOLATILE SECURITY DEFINER;

来源

2016-07-07 18:40:43

PostgreSQL。创建嵌套的JSON对象

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