严格的标准：只有变量应该通过参考请

Question

严格的标准进行传递：在请只变量应该按引用传递

if(isset($_FILES['image'])){ 
    $errors= array(); 
    $file_name = $_FILES['image']['name']; 
    $file_size =$_FILES['image']['size']; 
    $file_tmp =$_FILES['image']['tmp_name']; 
    $file_type=$_FILES['image']['type']; 
    $file_ext=strtolower(end(explode('.',$_FILES['image']['name']))); 

    $expensions= array("jpeg","jpg","png","docx","pdf"); 

    if(in_array($file_ext,$expensions)=== false){ 
    $errors="<div align='center'><font color='red'>extension not allowed, please choose a JPEG or PNG file.</font></div>"; 
    } 

Answer 1

内置end预计按引用传递的数组。所以传递的数组必须是一个变量。

$var = explode('.',$_FILES['image']['name']); 
    $file_ext=strtolower(end($var)); 

This means you must pass it a real variable and not a function returning an array