3
需要与此表上创建一个计算列一些帮助:
USE [ScienceWorksSummary]
GO
/****** Object: Table [dbo].[Authors_Articles] Script Date: 04/07/2011 10:38:55 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[Authors_Articles](
[IdAuthor] [int] NOT NULL,
[IdArticle] [int] NOT NULL,
[Part] [float] NULL,
CONSTRAINT [PK_Authors_Articles] PRIMARY KEY CLUSTERED
(
[IdAuthor] ASC,
[IdArticle] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
计算列(部分)的关键是让每个作者,即写了同一篇文章的工作的一部分。因此,例如,如果idAuthor = 1,idArticle = 1且idAuthor = 2,idArticle = 1,则 ,那么每个元素的Part必须为0.5。
感谢您的帮助!
谢谢! :)将1.0/count(*)更改为ROUND((1.0/count(*)),2)并且获得了我需要的东西! – DeadDream 2011-04-07 08:31:46