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我想用卷曲扩展来保存一些输入。用字符串中的空格进行Bash卷曲扩展
我的欲望膨胀:
-e uncore_imc0/cas_count_read/ -e uncore_imc1/cas_count_read/ -e uncore_imc2/cas_count_read/ -e uncore_imc3/cas_count_read/ -e uncore_imc4/cas_count_read/ -e uncore_imc5/cas_count_read/ -e uncore_imc6/cas_count_read/ -e uncore_imc7/cas_count_read/
我已经试过:
-e uncore_imc{0..7}/cas_count_read/
但这只是(仅在年初-e)扩大到
-e uncore_imc0/cas_count_read/ uncore_imc1/cas_count_read/ uncore_imc2/cas_count_read/ uncore_imc3/cas_count_read/ uncore_imc4/cas_count_read/ uncore_imc5/cas_count_read/ uncore_imc6/cas_count_read/ uncore_imc7/cas_count_read/
如果我试过了:
{-e, uncore_imc{0..7}/cas_count_read/}
或
"-e uncore_imc{0..7}/cas_count_read/"
无论将扩大。
尝试' “-e uncore_imc”{0..7}/cas_count_read /' – 123
@ 123,其导致'-e uncore_imc0/cas_count_read'是单个字传递给命令作为一个参数,而不是两个单独的参数'-e'和'uncore_imc0/cas_count_read'。 – chepner
@ 123,您的解决方案实际上适用于我。看起来只要字符串(带/不带引号)没有空格连接起来,它会扩展整个事物,这很好! – Patrick