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我的季节时间是次年的10月1日至3月31日。我如何创建一个赛季一个虚拟变量来看到这个人在进出在R中创建季节变量
df <- data.frame(ID= c(1:6),
Drug = c("A","C","A","A","B","A"),
Start = c("01/01/2009","07/10/2010","10/10/2009","03/01/2011","03/01/2012","04/12/2010"),
End=c("09/10/2009","04/20/2011","07/20/1010","01/01/2012","04/01/2013","09/30/2011"))
我的输出曝光:
ID Drug Start End Season
1 1 A 01/01/2009 09/10/2009 1
2 1 A 01/01/2009 09/10/2009 0
3 2 C 07/10/2010 04/20/2011 0
4 2 C 07/10/2010 04/20/2011 1
5 2 C 07/10/2010 04/20/2011 0
6 3 A 10/10/2009 07/20/1010 1
7 3 A 10/10/2009 07/20/1010 0
8 3 A 10/10/2009 07/20/1010 1
9 4 B 03/01/2011 01/01/2012 1
10 4 B 03/01/2011 01/01/2012 0
11 4 B 03/01/2011 01/01/2012 1
12 5 A 03/01/2012 04/01/2013 1
13 5 A 03/01/2012 04/01/2013 0
14 5 A 03/01/2012 04/01/2013 1
15 5 A 03/01/2012 04/01/2013 0
16 6 A 04/12/2010 09/30/2011 0
ID 1:她从01/01和09/10末开始。
[01/01, 03/31] =1
[03/31,09/10] = 0
ID 2:她从07/10/10开始,04/20结束。我检查
[07/10, 10/01] = 0
[10/01,03/31] = 1
[03/31, 04/20] = 0
ID5她开始03/01和04/01结束
[03/01, 03/31]= 1
[03/31, 10/01] = 0
[10/01, 03/31] = 1
[03/31, 04/01] = 0
我不清楚你在问什么。因此,患者2获得了三排季节0,1,0,因为她在赛季外开始,经历了赛季,并在赛季之外结束了赛季? – lebelinoz
患者5获得四排,因为她经历了四个时期(两个赛季和两个淡季)? – lebelinoz
她从07/10/2010开始到2011年4月20日结束,因此我检查[07/10,10/01] = 0,然后[10/1,03/31] = 1,[03/31/04/20] = 0 – BIN