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我已经修改了不错的AlainRo的Block for我的需要(不幸的是无法链接到它,因为没有足够的信誉),我无法删除旧数据图表后输入新数据。 There is my codepen。在另一个example我已经添加merge(),并且图表很好地对齐,但旧的仍然可见并且文本值被遗漏。d3js v4无法删除更新后的旧数据图表
我花了很多时间在上面,而且我没有想法。
有代码
barData = [
{ index: _.uniqueId(), value: _.random(1, 20) },
{ index: _.uniqueId(), value: _.random(1, 20) },
{ index: _.uniqueId(), value: _.random(1, 20) }
];
var margin = {top: 20, right: 20, bottom: 50, left: 70},
width = 400 - margin.left - margin.right,
height = 400 - margin.top - margin.bottom,
delim = 4;
var scale = d3.scaleLinear()
.domain([0, 21])
.rangeRound([height, 0]);
var x = d3.scaleLinear()
.domain([0, barData.length])
.rangeRound([0, width]);
var y = d3.scaleLinear()
.domain([0, 21])
.rangeRound([height, 0]);
var svg = d3.select('#chart')
.append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append('g')
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
svg.append("g")
.attr("transform", "translate(0," + height + ")")
.call(d3.axisBottom(x));
svg.append("g")
.call(d3.axisLeft(y));
function draw() {
x.domain([0, barData.length]);
var brush = d3.brushY()
.extent(function (d, i) {
return [[x(i)+ delim/2, 0],
[x(i) + x(1) - delim/2, height]];})
.on("brush", brushmove);
var svgbrush = svg.selectAll('.brush')
.data(barData)
.enter()
.append('g')
.attr('class', 'brush')
.append('g')
.call(brush)
.call(brush.move, function (d){return [d.value, 0].map(scale);});
svgbrush
.append('text')
.attr('y', function (d){return scale(d.value) + 25;})
.attr('x', function (d, i){return x(i) + x(0.5);})
.attr('dx', '-.60em')
.attr('dy', -5)
.style('fill', 'white')
.text(function (d) {return d3.format('.2')(d.value);});
svgbrush
.exit()
.append('g')
.attr('class', 'brush')
.remove();
function brushmove() {
if (!d3.event.sourceEvent) return; // Only transition after input.
if (!d3.event.selection) return; // Ignore empty selections.
if (d3.event.sourceEvent.type === "brush") return;
var d0 = d3.event.selection.map(scale.invert);
var d = d3.select(this).select('.selection');;
var d1 =[d0[0], 0];
d.datum().value = d0[0]; // Change the value of the original data
d3.select(this).call(d3.event.target.move, d1.map(scale));
svgbrush
.selectAll('text')
.attr('y', function (d){return scale(d.value) + 25;})
.text(function (d) {return d3.format('.2')(d.value);});
}
}
draw();
function upadateChartData() {
var newBarsToAdd = document.getElementById('charBarsCount').value;
var newBarData = function() {
return { index: _.uniqueId(), value: _.random(1, 20) }
};
newBarData = _.times(newBarsToAdd, newBarData);
barData = _.concat(barData, newBarData)
draw();
};
是否也可以去除交叉指针,只留下调整,当我拖着顶部栏边框?