我想在Android上通过递归目录搜索将搜索字符串与文件名匹配。问题是这些字符是日语,并且在某些情况下不匹配。例如,我试图匹配文件名称的开头的搜索字符串是“呼ぶ”。当我从file.getName()打印文件名时,这是准确反映的,例如打印到控制台的文件名称以“呼ぶ”开头。但是当我在搜索字符串上进行匹配时,例如fileName.startwith(“呼ぶ”),它不匹配。Android,日文字符文件名比较问题
事实证明,当我打印正在搜索的文件名的子字符串时,第二个字符不同 - 单词是“呼ふ”而不是“呼ぶ”。如果我提取字节并打印十六进制字符,则最后一个字节会关闭1 - 大概是“ぶ”和“ふ”之间的差异。
这里是用来以示区别的代码:
String name = soundFile.getName();
String string1 = question.kanji;
Log.d(TAG, "searching for : s1:" + question.kanji + " + " + question.hiragana + " + " + question.english);
Log.d(TAG, "name is: " + name);
Log.d(TAG, "question.kanaji.length(): " + question.kanji.length());
Log.d(TAG, "question.hiragana.length(): " + question.hiragana.length());
String compareStart = name.substring(0, string1.length());
Log.d(TAG, "string1.length(): " + string1.length());
Log.d(TAG, "compareStart.length(): " + compareStart.length());
byte[] nameUTF8 = null;
byte[] s1UTF8 = null;
byte[] csUTF8 = null;
nameUTF8 = name.getBytes();
s1UTF8 = string1.getBytes();
csUTF8 = compareStart.getBytes();
Log.d(TAG, "nameUTF8.length: " + s1UTF8.length);
Log.d(TAG, "s1UTF8.length: " + s1UTF8.length);
Log.d(TAG, "csUTF8.length: " + csUTF8.length);
for (int i = 0; i < s1UTF8.length; i++) {
Log.d(TAG, "s1UTF8[i]: " + Integer.toString(s1UTF8[i] & 0xff, 16).toUpperCase());
}
for (int i = 0; i < csUTF8.length; i++) {
Log.d(TAG, "csUTF8[i]: " + Integer.toString(csUTF8[i] & 0xff, 16).toUpperCase());
}
for (int i = 0; i < nameUTF8.length; i++) {
Log.d(TAG, "nameUTF8[i]: " + Integer.toString(nameUTF8[i] & 0xff, 16).toUpperCase());
}
的部分输出如下:
D/AnswerView(12078): searching for : s1:呼ぶ + よぶ + to call out,to invite
D/AnswerView(12078): name is: 呼ぶ よぶ to call out,to invite.mp3
D/AnswerView(12078): question.kanaji.length(): 2
D/AnswerView(12078): question.hiragana.length(): 2
D/AnswerView(12078): string1: 呼ぶ
D/AnswerView(12078): compareStart: 呼ふ
D/AnswerView(12078): string1.length(): 2
D/AnswerView(12078): compareStart.length(): 2
D/AnswerView(12078): string1.length(): 2
D/AnswerView(12078): compareStart.length(): 2
D/AnswerView(12078): nameUTF8.length: 6
D/AnswerView(12078): s1UTF8.length: 6
D/AnswerView(12078): csUTF8.length: 6
D/AnswerView(12078): s1UTF8[i]: E5
D/AnswerView(12078): s1UTF8[i]: 91
D/AnswerView(12078): s1UTF8[i]: BC
D/AnswerView(12078): s1UTF8[i]: E3
D/AnswerView(12078): s1UTF8[i]: 81
D/AnswerView(12078): s1UTF8[i]: B6
D/AnswerView(12078): csUTF8[i]: E5
D/AnswerView(12078): csUTF8[i]: 91
D/AnswerView(12078): csUTF8[i]: BC
D/AnswerView(12078): csUTF8[i]: E3
D/AnswerView(12078): csUTF8[i]: 81
D/AnswerView(12078): csUTF8[i]: B5
D/AnswerView(12078): nameUTF8[i]: E5
D/AnswerView(12078): nameUTF8[i]: 91
D/AnswerView(12078): nameUTF8[i]: BC
D/AnswerView(12078): nameUTF8[i]: E3
D/AnswerView(12078): nameUTF8[i]: 81
D/AnswerView(12078): nameUTF8[i]: B5
D/AnswerView(12078): nameUTF8[i]: E3
D/AnswerView(12078): nameUTF8[i]: 82
D/AnswerView(12078): nameUTF8[i]: 99
D/AnswerView(12078): nameUTF8[i]: 20
D/AnswerView(12078): nameUTF8[i]: 20
D/AnswerView(12078): nameUTF8[i]: 20
D/AnswerView(12078): nameUTF8[i]: 20
显示该文件名的所提取的子的第六个字节,作为以及文件名本身,是“B5”而不是“B6”,因为它在搜索字符串中。但是,打印的文件名正确显示。我很难过。为什么当底层字符不同时,文件名正确显示给控制台?为什么在文件名的开头还有另外3个非空白字节 - 在搜索字符串中不需要某种方式来表示“ぶ”字符?
这解释了这个问题。由于额外的三个字节,文件名必须在NFD中,这将是将“ふ”转换为“ぶ”的额外的波形。我找到了一个解释这个的链接,以及Java中的解决方案(使用Normalizer),非常好:http://weblogs.java.net/blog/joconner/archive/2007/02/normalization_c.html – 2011-04-28 03:36:37