我无法在原型的Ajax.Request类中获取正确的作用域。我正在试图做的是写一个简单的API,它包装的Ajax请求:原型和Ajax.Request范围
API = Class.create({
initialize:function(api_token)
{
this.api_token = api_token;
this.request_uri = new Template('/api/#{api_token}/#{resource}.json');
this.status = 0;
this.last_result = null;
},
some_api_call:function()
{
var result = this._request('resource', {'id':1});
// and so on...
},
_request:function(resource, params)
{
var uri = this.request_uri.evaluate({"api_token":this.api_token,"resource":resource});
new Ajax.Request(uri,
{
contentType:'application/json',
method:'get',
parameters:params,
onSuccess:function(r)
{
alert(this);
this.last_result = r.responseJSON;
this.status = r.status;
}
});
return this.last_result;
}
});
当我在我预期的onSuccess()方法是+这+来指代父对象,但它给我DOMWindow。我似乎无法将该响应数据放入API类中。我认为这是愚蠢的(绑定?),但我似乎今天似乎无法想到这一个。
谢谢