我想添加一个图像文件到我的PHP,所以当我回声时,图片将出现在消息旁边。但是我收到了第3行的语法错误。任何帮助将不胜感激。PHP img src(简单)
<?php
echo "President has been killed";
<IMG SRC = "D:/User Data\Documents/Sheridan/Summer Year 3/Enterprise Java Development/Projects/PhpAssignment/skull.png;"/>
?>
我想添加一个图像文件到我的PHP,所以当我回声时,图片将出现在消息旁边。但是我收到了第3行的语法错误。任何帮助将不胜感激。PHP img src(简单)
<?php
echo "President has been killed";
<IMG SRC = "D:/User Data\Documents/Sheridan/Summer Year 3/Enterprise Java Development/Projects/PhpAssignment/skull.png;"/>
?>
<?php
echo 'President has been killed
<img src="D:/User Data\Documents/Sheridan/Summer Year 3/Enterprise Java Development/Projects/PhpAssignment/skull.png;" /> ';
?>
注意引号的变化 - 分号和布局 - 单双。
或
<?php
echo "President has been killed";
?>
<img src="D:/User Data\Documents/Sheridan/Summer Year 3/Enterprise Java Development/Projects/PhpAssignment/skull.png;" />
移动图像外 PHP的。尽管如此,使用这取决于整体标记。
分号结束,或停止echo
声明。
当然有一个语法错误。您正试图输出HTML PHP块中:
你的代码更改为:
<?php
echo "President has been killed";
?>
<IMG SRC = "D:/User Data\Documents/Sheridan/Summer Year 3/Enterprise Java Development/Projects/PhpAssignment/skull.png;"/>
<?php
echo "President has been killed";
<IMG SRC = "D:/User Data\Documents/Sheridan/Summer Year 3/Enterprise Java Development/Projects/PhpAssignment/skull.png;"/>
?>
首先你不需要整个位置,将图像在你的根被称为图像的文件夹中然后将图像放在那里。
<?php
echo '<p>President has been killed<p><img src = "D:/User Data\Documents/Sheridan/Summer Year 3/Enterprise Java Development/Projects/PhpAssignment/skull.png"/>';
?>
结束标记'?>'必须在'
HTML tags are usually written in lower case, ditto attributes, so use ''之前。还要注意''''周围没有空格。你大概可以逃避大写和/或空格,因为浏览器往往非常宽容,但最好遵守标准。 – halfer
此外,您的图片只会在指定文件夹下工作 - 如果您的HTML文件与“skull.png”位于同一文件夹中,则只需使用“”而不是使用整个路径名称。 – halfer