如何创建XSLT样式表

Question

我可以访问Schematron xsl文件和Schematron sch文件。我如何使用C＃将它转换成XSLT样式表？

xsl + sch - > [??? XSLT处理器？ ] - > xslt样式表

Answer 1

回答我自己的问题... 这个工作，不幸的是，Schematron文件只支持使用XslCompiledTransform的非常简单的语法。在SAXON上看到它的作品:(

 string xmlFile = @"sch\patient.sch"; 
     string xslFile = @"xsl\conformance1-5.xsl"; 
     XslCompiledTransform xsltransform = new XslCompiledTransform(); 
     xsltransform.Load(xslFile); 

     XmlDocument doc = new XmlDocument(); 
     doc.Load(xmlFile); 
     XPathNavigator nav = doc.CreateNavigator(); 

     System.IO.MemoryStream st = new System.IO.MemoryStream(); 
     xsltransform.Transform(nav, null, st); 
     st.Position = 0; 
     System.IO.StreamReader rd = new System.IO.StreamReader(st); 
     string xslt = rd.ReadToEnd(); 

     System.Diagnostics.Debug.WriteLine(xslt); 

     XmlReader reader = XmlReader.Create(new System.IO.StringReader(xslt)); 
     xsltransform.Load(reader); 

     var patient = PatientFactory.GeneratePatientBySOAPClasses(); 
     patient.identifier[0].period.end.value = DateTime.Now.ToString("yyyy-MM-dd"); 
     patient.identifier[0].period.start.value = DateTime.Now.AddYears(15).ToString("yyyy-MM-dd"); 
     patient.identifier[0].period.start = null; 

     string xml = Serialization.SerializeXML(patient, "http://hl7.org/fhir"); 

     xml = xml.Replace("xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns=\"http://hl7.org/fhir\"", ""); 
     doc.LoadXml(xml); 
     nav = doc.CreateNavigator(); 

     st = new System.IO.MemoryStream(); 
     xsltransform.Transform(nav, null, st); 
     st.Position = 0; 
     rd = new System.IO.StreamReader(st); 
     string scematronresult = rd.ReadToEnd();