移动大记录表的最快方法mysql

Question

请帮我看看这个solution.im处理一个非常大的数据记录，如2M的学生测试结果记录。所有记录都存储在一个表中，我需要做的是单独这个记录分成两个不同的表格，一个用于所有通过学生，另一个用于失败学生。在分开这个记录之后，我需要从源表格中删除原始记录。每当我运行这个代码时，它需要几个小时才能完成。如果任何人都可以帮助我找出解决方案，这将是非常棒的。谢谢。

这里是示例代码：

<?php ob_start(); ?> 
<?php 
function spread($classselect,$subjectselect) 
{include "connectdb.php"; 

//movepass 

$selectpass = mysql_query("SELECT * FROM testresultAUG2012 WHERE actualmonth='AUG' AND testresult = 'PASS' AND classname = '$classselect' AND educationsubject = $subjectselect;",$conn); 
$totalpass = mysql_num_rows($selectpass); 
$pass=0; 
while($pass<$totalpass) 
{ 
    $name=mysql_result($selectpass, $pass, "Studentname"); 
    $subject=mysql_result($selectpass, $pass, "Subject"); 
    $testbatch=mysql_result($selectpass, $pass, "testbatch"); 
    $classname=mysql_result($selectpass, $pass, "class"); 
    $lecturer=mysql_result($selectpass, $pass, "lecturer"); 
    $date=mysql_result($selectpass, $pass, "date"); 
    $month=mysql_result($selectpass, $pass, "month"); 
    $time=mysql_result($selectpass, $pass, "time"); 
    $state=mysql_result($selectpass, $pass, "result"); 

    //count total pass subject and add 1 
    $totalpass = mysql_query("SELECT * FROM Student WHERE Studentname = '$name';",$conn); 
    $only = mysql_fetch_array($theone); 
    $currentpass = $only['totalpass']; 
    $newpass = $currentpass + 1; 
    mysql_query("UPDATE Student SET totalpass = $newpass WHERE Studentname = '$name';",$conn); 

    //save record to pass table 
    mysql_query("INSERT INTO passtab(......) VALUES(....);",$conn); 

    //remove data from origin table 
    mysql_query("DELETE FROM testresultAUG2012 WHERE Studentname = '$name' AND testbatch = $testbatch AND Subject=$subject AND result = 'PASS' AND class = '$classname';",$conn); 
    $pass++; 
} 

//moveFailed 

$selectfail = mysql_query("SELECT * FROM testresultAUG2012 WHERE actualmonth='AUG' AND testresult = 'PASS' AND classname = '$classselect' AND educationsubject = $subjectselect;",$conn); 
$totalfail = mysql_num_rows($selectfail); 
$fail=0; 
while($fail<$totalfail) 
{ 
    $name=mysql_result($selectfail, $fail, "Studentname"); 
    $subject=mysql_result($selectpass, $fail, "Subject"); 
    $testbatch=mysql_result($selectfail, $fail, "testbatch"); 
    $classname=mysql_result($selectfail, $fail, "class"); 
    $lecturer=mysql_result($selectfail, $fail, "lecturer"); 
    $date=mysql_result($selectfail, $fail, "date"); 
    $month=mysql_result($selectfail, $fail, "month"); 
    $time=mysql_result($selectfail, $fail, "time"); 
    $state=mysql_result($selectfail, $fail, "result"); 

    //count total fail subject and add 1 
    mysql_query("UPDATE Student SET totalfail = totalfail + 1 WHERE Studentname = '$name';",$conn); 

    //save record to fail table 
    mysql_query("INSERT INTO failtab(....) VALUES(...);",$conn); 


    //remove data from origin table 
    mysql_query("DELETE FROM testresultAUG2012 WHERE Studentname = '$name' AND testbatch = $testbatch AND Subject=$subject AND result = 'FAIL' AND class = '$classname';",$conn); 
    $fail++; 
    } 
} 
?> 
<?php 
$relatedclass=$_POST[classup]; 
$relatedsubject=$_POST[subject]; 
spread($relatedclass,$relatedsubject); 
echo "<center>Spread Completed !!!</CENTER>"; 

?> 
<? ob_flush(); ?> 

Answer 1

你不应该从数据库读取的所有数据，然后通过行发回重新排。

如果你的草坪上有一袋沙子，你想把它给邻居，你会怎么做？你会给他留下一张纸条，告诉他他可以拿走它吗？或者你会先把整个包子寄给你在俄罗斯的叔叔，然后告诉你的叔叔每次把它寄回给你的邻居一粒粮食？您处理数据的方式更像后一种方法。

做这样的事情，而不是：

INSERT INTO table1 
(col1, col2, ... coln) 
SELECT col1, col2, ... coln 
FROM table2 
WHERE result = 'PASS' 

Answer 2

你可以从while循环中删除查询和运行外循环查询，但生成loop.i内的查询字符串的意思，而不是每次查询运行你可以通过一个查询插入的所有数据，你可以尝试以下解决方案

while($pass<$totalpass) 
{ 
    $name=mysql_result($selectpass, $pass, "Studentname"); 
    $subject=mysql_result($selectpass, $pass, "Subject"); 
    $testbatch=mysql_result($selectpass, $pass, "testbatch"); 
    $classname=mysql_result($selectpass, $pass, "class"); 
    $lecturer=mysql_result($selectpass, $pass, "lecturer"); 
    $date=mysql_result($selectpass, $pass, "date"); 
    $month=mysql_result($selectpass, $pass, "month"); 
    $time=mysql_result($selectpass, $pass, "time"); 
    $state=mysql_result($selectpass, $pass, "result"); 

    //count total pass subject and add 1 
    $totalpass = mysql_query("SELECT * FROM Student WHERE Studentname = '$name';",$conn); 
    $only = mysql_fetch_array($theone); 
    $currentpass = $only['totalpass']; 
    $newpass = $currentpass + 1; 


    //save record to pass table 
    $values[]='('.$valuestring.')'(//whatever you want to ineser) 

    //remove data from origin table 

    $pass++; 
} 

的mysql_query（插入tyablename（ ''）值（破灭（ ''，$值）））