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有人可以帮助我吗? 我得到的SQL查询和需要来表示,在JPQL,但我遇到麻烦,右连接:JPQL多JOIN查询
SELECT alrt.*
FROM
REACTION.ALERT alrt, REACTION.INVESTIGATION inv,
REACTION.CLASSIFICATION_TYPE clst, REACTION.FRAUD_TYPE frt,
REACTION.TRANS trns, REACTION.CARD crd
WHERE
alrt.ISS_INST IN(1201, 1101) AND
alrt.MODULE_TYPE = 0 AND
0 < (SELECT COUNT(*) FROM REACTION.INVESTIGATION WHERE REACTION.INVESTIGATION.ALERT_ID = alrt.ID) AND
inv.CLASSIFICATION_TYPE_ID IS NOT NULL AND
clst.CLASSIFICATION_TYPE = 10 AND
(alrt.REMINDER_USER_LOGIN = 'qwr' OR alrt.REMINDER_USER_LOGIN IS NULL) AND
alrt.ID = inv.ALERT_ID AND
alrt.TRANSACTION_ID = trns.ID(+) AND inv.CLASSIFICATION_TYPE_ID =
clst.ID AND inv.FRAUD_TYPE_ID = frt.ID(+) AND trns.HPAN = crd.HPAN(+);
读教程和文档之后,我创建JPQL查询:
SELECT alrt
FROM INVESTIGATION inv
JOIN inv.CLASSIFICATION_TYPE_ID clst
RIGHT JOIN inv.FRAUD_TYPE_ID frt
JOIN inv.alert_id alrt
RIGHT JOIN alrt.transactio_id trns
RIGHT JOIN trns.HPAN crd
WHERE
alrt.ISS_INST IN(1201, 1101) AND
alrt.MODULE_TYPE = 0 AND 0 < (SELECT COUNT(inv1) FROM INVESTIGATION inv1 WHERE inv1.ALERT_ID = alrt.ID) AND
inv.CLASSIFICATION_TYPE_ID IS NOT NULL AND
clst.CLASSIFICATION_TYPE = 2 AND
(alrt.REMINDER_USER_LOGIN = 'qwr' OR alrt.REMINDER_USER_LOGIN IS NULL);
但我得到了错误,然后尝试执行该操作。有人可以告诉我做错了吗? 如果它是有道理的我使用JPA 1.0版本
你可以发布你得到的错误吗? – jmvivo 2014-10-22 08:01:14
好吧,我会在一个小时内添加错误文本,对不起 – MeetJoeBlack 2014-10-22 08:24:10