2011-01-08 112 views

回答

2

呃......是的!见https://github.com/nicholas22/jpropel-light

// create alphabet char[] 
    new Character('A').to(new Character('Z')).unbox(); 

    // join two arrays and put in list 
    alphabet.join(numerics).toList(); 

    // select distinct j* names, using LINQ-style statements 
    new String[] { "james", "john", "john", "eddie" }.where(startsWith("j")).distinct(); 
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