SUM返回错误的值时加入3表 - MS SQL

我有3个表需要加入即表发票，项目和支付。表项目和支付将加入到表发票基于发票编号SUM返回错误的值时加入3表 - MS SQL

现在我需要得到SUM 的销售，销售成本和支付后按发票日期。

所以这是我的查询

SELECT SUM((I.price * qty) - (I.price * qty * discount)) as totalSales,SUM((I.price * qty) - (I.price * qty * discount)-costItem) as salesAfterCost, SUM(PAY.amount) as paymentReceived 
FROM tbl_inv B LEFT JOIN tbl_item I ON B.id = I.id_invoice 
LEFT JOIN tbl_payment PAY ON B.id = PAY.id_invoice 
WHERE B.dateInv = '2013-04-01' 
GROUP BY B.id,b.dateInv;

并把结果返回这样

totalSales salesAfterCost paymentReceived 
75.540000 67.540000  622.8000

但是，当我与此查询核实，以获取支付总额，它会与不同的价值回归。

SELECT SUM(PAY.amount) paymentReceived 
FROM tbl_inv B LEFT JOIN tbl_payment PAY ON B.id = PAY.id_invoice 
WHERE B.dateInv = '2013-04-01';

结果：

paymentReceived 
155.7000

，查询销售

SELECT SUM((I.price * qty) - (I.price * qty * discount)) as totalSales,SUM((I.price * qty) - (I.price * qty * discount)-costItem) as salesAfterCost 
FROM tbl_inv B LEFT JOIN tbl_item I ON B.id = I.id_invoice 
WHERE B.dateInv = '2013-04-01';

结果：

totalSales salesAfterCost 
37.770000 33.770000

我怎样才能解决这个事情？

来源

2013-05-01 Chuki2

@Damien_The_Unbeliever是正确的。但是，如果您可以将付款加入发票上的特定项目，也可以解决。 – davmos 2013-05-01 07:17:49

@davmos - 考虑到付款乘以4，销售额乘以2，我不认为发票和付款之间存在1-1对应关系。 – 2013-05-01 07:20:33

当然@Damien_The_Unbeliever，但我没有这么说。我只是暗示了**发票上的项目**与付款之间的1-1关系的可能性。可能不可能，但我认为我会把它放到混合中来帮助理解。 – davmos 2013-05-01 07:28:25

移动SUM() s转换的子查询 - 此刻，从支付每一行正在对每一行从发票匹配，造成了笛卡儿连接

SELECT I.totalSales,I.salesAfterCost, PAY.paymentReceived 
FROM tbl_inv B 
LEFT JOIN (
    select id_invoice,SUM((I.price * qty) - (I.price * qty * discount)) as totalSales, 
     SUM((I.price * qty) - (I.price * qty * discount)-costItem) as salesAfterCost 
    from tbl_item group by id_invoice) I 
     ON 
     B.id = I.id_invoice 
LEFT JOIN (
    select id_invoice,SUM(amount) as paymentReceived 
    from tbl_payment group by id_invoice) PAY 
     ON 
     B.id = PAY.id_invoice 
WHERE B.dateInv = '2013-04-01'

来源

2013-05-01 07:10:21

谢谢你的帮助，像冠军一样工作 – Chuki2 2013-05-01 15:15:57

SUM返回错误的值时加入3表 - MS SQL

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