我写了一个密码生成器,我遇到了这个烦人的问题,它是在同一行重复一个数字或字母。用户给程序一个格式,说明他们希望如何生成他们的密码,例如“C @@ d %%%” 其中@只是字母,而%只是数字,用户还输入数字和字母以生成密码,那么该程序是假设打印出像cold123这样的东西,而是打印出cood111或clld111,我会在下面发布我的代码片段,但请不要说坏话,我对python相当陌生,自学成才,几个月后进入蟒蛇体验。如何阻止我的程序生成相同的密钥?
class G()
.
.
.
# self.forms is the format the user input they can input things such as [email protected]@d%%%
# where @ is only letters and where % is only numbers
# self.Bank is a list where generated things go
AlphaB = [] #list Of All Of The Positions That have The @ sign in The self.forms
NumB = [] #list of All of the positions that have a % sign
for char in self.forms:
if char == '@':
EOL=(self.Position) # Positions End Of Line
Loc = self.forms[EOL] # Letter
AlphaB.append(EOL)
if char == '%':
EOL=(self.Position)
Loc = self.forms[EOL]
NumB.append(EOL)
self.Position+=1 # Move right a position
for pos in AlphaB:
for letter in self.alphas: #letters in The User Inputs
GenPass=(self.forms.replace(self.forms[pos],letter))
#Not Fully Formatted yet, because Only The letter been formatted
if GenPass.find('%'):
for Pos in NumB:
for number in self.ints:
GenPass=(GenPass.replace(GenPass[Pos],number))
if GenPass not in self.Bank:
#Cood111
print (GenPass)
self.Bank.append(GenPass)
else:
if GenPass not in self.Bank:
print (GenPass)
self.Bank.append(GenPass)
这是一个练习,对不对? – l0b0
我认为问题是'replace()'函数我相信如果你传递第三个参数',1',那么只有第一个匹配项会被替换,而不是所有的匹配项 – depperm