在我的代码错误，但我无法找出如何修复

Question

无法连接到数据库。 我的错误：

[Sat Jul 29 23:02:56.747139 2017] [proxy_fcgi:error] [pid 13049:tid 140689614522112] [] AH01071: Got error 'PHP message: PHP Warning: mysqli::mysqli(): (HY000/1045): Access denied for user 'timavnl_1'@'localhost' (using password: YES) in /home/timavnl/domains/tim-av.nl/public_html/6628/job/db_connect.php on line 2\nPHP message: PHP Warning: mysqli::prepare(): Couldn't fetch mysqli in /home/timavnl/domains/tim-av.nl/public_html/6628/job/index.php on line 5\nPHP message: PHP Warning: main(): Couldn't fetch mysqli in /home/timavnl/domains/tim-av.nl/public_html/6628/job/index.php on line 10\nPHP message: PHP Notice: Trying to get property of non-object in /home/timavnl/domains/tim-av.nl/public_html/6628/job/index.php on line 23\nPHP message: PHP Fatal error: Call to a member function fetch() on null in /home/timavnl/domains/tim-av.nl/public_html/6628/job/index.php on line 24\n'

我的DB连接代码：

<?php 
$db = new mysqli("localhost","timavnl_1","password"."timavnl_1") or 
die("ERROR! With connection"); 
?> 

的index.php代码： Picture of: index.php

Answer 1

你有一个错字错。您设置了密码后给予.，与,改变这一点，这样使用

"<"?php $db = new mysqli("localhost","timavnl_1","password","timavnl_1") or die("ERROR! With connection"); ?> 

正确的语法为使connection对象，参数必须由,运营商sephrated。

语法

$mysqli = new mysqli("localhost", "user", "password", "database"); 

注：根据所使用的connection功能，各种参数可以omitted。如果未提供参数，则该扩展尝试使用在PHP配置文件中设置的默认值。检查手册here

Answer 2

数据库连接代码在密码和数据库名称之间似乎有一段时间.而不是,。

裁判：http://php.net/manual/en/mysqli.quickstart.connections.php

尝试，而不是执行以下操作：

"<"?php $db = new mysqli("localhost","timavnl_1","password","timavnl_1") or die("ERROR! With connection"); ?>