我有一个JSON对象是这样的:angularjs:推不是一个函数
var post = {
"post_id": "1",
"content": "content",
"post_author": {
"id": "12",
"firstName": "Amelia",
"lastName": "Earheart",
},
"isLiked": false,
"likes_count": 0,
"likers": [],
"comments_count": 0,
"commenters": [],
"comments": []
};
而且post
传递到从前端下面给出的函数。
var vm = this;
vm.likePost = function(post) {
var likedPost = post;
vm.userInfo();
likedPost.likers.push(userObject); //Here
myService.postLike(likedPost).success(function(data) {
likedPost.isLiked = true;
likedPost.likes_count++;
vm.posts = data;
});
};
但这样做,我得到一个JavaScript错误的行话说push is not a function
likedPost.likers.push(userObject);
而且userObject
由vm.userInfo()
返回,它看起来像这样:
vm.userInfo = function() {
myService.getBasicUserInfo().success(function(data) {
vm.currentPost.post_author.id = data.id;
vm.currentPost.post_author.firstName = data.firstName;
vm.currentPost.post_author.lastName = data.lastName;
});
};
和返回的JSON像这个:
{"id":"12","firstName":"Amelia","lastName":"Earheart"}
任何人都可以帮我找出这个问题的原因吗?
UPDATE:
{
"post_id": "12",
"content": "Content is the content that contains the content",
"image": "member-default.jpg",
"created_at": "2016-05-26 14:29:00",
"post_author": {
"id": "12",
"firstName": "Amelia",
"lastName": "Earheart",
},
"isLiked": false,
}
这是我所得到的在console.log(likedPost);
在推送电话之前,您可以添加以下内容: console.log(likedPost); 并发送结果 – Silvinus
好的。给我一点时间。 @Silvinus – Annabelle
这个错误意味着''likers'不是一个数组 –