过滤特定字典

Question

d = {'id': 'ccccc', 
    'school': [{'s_id': '12', 'city': 'xxx'}, {'s_id': '11', 'city':'yy'}]} 

我想使用s_id对其进行过滤。假设如果某人想过滤s_id = 11它应该返回{'s_id': '11', 'city':'yy'}.请使用filter关键字回答。

Answer 1

>>> s_id=11 
>>> [i for i in d['school'] if i['s_id'] == str(s_id)] 
[{'s_id': '11', 'city': 'yy'}] 

Answer 2

这是使用filter和部分功能。

#!/usr/bin/env python 

from functools import partial 

d = {'id': 'ccccc','school': [{'s_id': '12', 'city': 'xxx'}, {'s_id': '11', 
'city':'yy'}]} 

def myfilter(school, s_id): 
    return school['s_id'] == str(s_id) 

f = partial(myfilter, s_id = 11) 
print filter(f, d['school']) 

Answer 3

只需使用Python内置过滤功能：

>>> filter(lambda d:d['s_id']=='11',d['school']) 
[{'s_id': '11', 'city': 'yy'}] 

作为奖励，如果你想通过 'S_ID' 进行排序，你可以这样做：

>>> for school in sorted(d['school'],key=lambda d:d['s_id']): 
...  print school 
... 
{'s_id': '11', 'city': 'yy'} 
{'s_id': '12', 'city': 'xxx'}