我想运行下面的代码与Apache的公共,为了把它写入到CSV文件。 finalResult
数组的打印语句显示它具有我想要填充的内容。由于某种原因,它不会将数据发送到指定的csv。数据没有被写入到csv与Apache Commons
public void handle(ActionEvent runButton) {
String csvFile = (userHomeFolder + "/" + fileName.getText() + ".csv");
FileWriter writer = new FileWriter(csvFile);
try {
final Object [] FILE_HEADER = columnHeaders.toArray();
int modval = 2;
final String NEW_LINE_SEPARATOR = "\n";
FileWriter fileWriter;
CSVPrinter csvFilePrinter;
CSVFormat csvFileFormat = CSVFormat.DEFAULT.withRecordSeparator(NEW_LINE_SEPARATOR);
List rowResult = new ArrayList();
fileWriter = new FileWriter(fileName.getText());
csvFilePrinter = new CSVPrinter(fileWriter, csvFileFormat);
try {
//CREATE CSV FILE HEADER
System.out.println("File header: " + FILE_HEADER);
csvFilePrinter.printRecord(FILE_HEADER);
for(int y = 0; y < finalResult.size(); y++) {
if(y % modval == 0) {
rowResult.add(finalResult.get(y));
csvFilePrinter.printRecord(rowResult);
System.out.println(rowResult);
rowResult.clear();
}else {
//this means it is not the last value in the row
rowResult.add(finalResult.get(y));
System.out.println("fr: " + finalResult.get(y));
}
}
} catch (Exception e) {
System.out.println("Error in csvFileWriter");
e.printStackTrace();
} finally {
try {
fileWriter.flush();
fileWriter.close();
csvFilePrinter.close();
} catch (IOException e) {
System.out.println("Error while flushing/closing");
}
}
}
}
//below catches any errors for any of the above work
catch (Exception e) {
e.printStackTrace();
System.err.println(e.getMessage());
}
您使用不带'catch'或'finally'或资源声明的传统'try',这就是为什么不能编译!此外,在wirter使用它们之后,最好关闭潜在的作者,因为你不知道他们是否使用缓冲...... – fabian
你可以将finalResult的内容添加到问题中。当你执行你看到的两个打印输出结果时你也看到了什么? – digidude
为什么你有两个'FileWriter's?看来你只能写信给其中一个人 - 这不是带有'csv'后缀的人吗? – Itai