IA-32和x86-64 POP指令中的汇编

Question

pop ebp在代码的ret（返回）指令之前在IA-32和x86-64机器中的含义是什么？所以我确实有新的和新的ebp，并且新的ebp通过函数的调用被推入堆栈。那么这个ebp是pop'ed？ pop指令如何更改ebp的值？

Answer 1

PUSH EAX 

主要是指：

SUB ESP,4 
MOV [ESP],EAX 

而且

POP EAX 

方式：

MOV EAX,[ESP] 
ADD ESP,4 

---

当你谈论老新的EBP我想你是指的功能序言和结尾？

PUSH EBP  ; Store caller's EBP on the stack 
MOV EBP,ESP ; Set EBP to the current stack pointer 

; Here we can do things like: 
MOV EAX,[EBP+8] 
PUSH EAX 
MOV EBX,[EBP+12] 
POP EAX 
; ..to access the stack. Since we've got a fixed reference point for 
; the stack in EBP we don't have to worry about the stack pointer 
; changing. 

; For example, we could do this instead to access the same stack 
; elements as above: 
MOV EAX,[ESP+8] 
PUSH EAX 
MOV EBX,[ESP+16] 
POP EAX 
; But notice that we had to change the second offset since the push 
; instruction changed the stack pointer. It's obviously easier to deal 
; with a base address that doesn't change every time we execute 
; certain instructions. 

MOV ESP,EBP ; Restore the stack pointer 
POP EBP  ; Restore the caller's EBP before returning