2010-01-21 89 views
3

在windows应用程序中,我使用w32tm强制计算机将时间与特定的时间资源同步。 但现在我正在做一个WM5.0上的PDA应用程序,w32tm不再可用,并且不知道如何在谷歌搜索之后开始。我如何在WM上同步互联网资源?

回答

4

Here is a good example

为了完整起见,这里是从博客文章的代码:

public DateTime GetNTPTime() 
{ 
    // 0x1B == 0b11011 == NTP version 3, client - see RFC 2030 
    byte[] ntpPacket = new byte[] { 0x1B, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
          0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
          0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
          0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
          0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 
          0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00 }; 

    IPAddress[] addressList = Dns.GetHostEntry("pool.ntp.org").AddressList; 

    if (addressList.Length == 0) 
    { 
     // error 
     return DateTime.MinValue; 
    } 

    IPEndPoint ep = new IPEndPoint(addressList[0], 123); 
    UdpClient client = new UdpClient(); 
    client.Connect(ep); 
    client.Send(ntpPacket, ntpPacket.Length); 
    byte[] data = client.Receive(ref ep); 

    // receive date data is at offset 32 
    // Data is 64 bits - first 32 is seconds - we'll toss the fraction of a second 
    // it is not in an endian order, so we must rearrange 
    byte[] endianSeconds = new byte[4]; 
    endianSeconds[0] = data[32 + 3]; 
    endianSeconds[1] = data[32 + 2]; 
    endianSeconds[2] = data[32 + 1]; 
    endianSeconds[3] = data[32 + 0]; 
    uint seconds = BitConverter.ToUInt32(endianSeconds, 0); 

    return (new DateTime(1900, 1, 1)).AddSeconds(seconds); 
} 
+1

非常好编辑:d – geogeek 2013-04-15 15:04:22