如何将单元格值绑定到对象上的特定属性？

Question

我有一个是在与以下类型的细胞水平填充的DataTable：

public class GridCell 
{ 
    public string Value { get; set} 
    public Guid Id { get; set; } 
} 

我绑定的DataTable添加到WPF工具包的DataGrid，但这些细胞都上来了空。如何告知DataGrid查看GridCell类型的单元格内容的Value属性？

结合片段：

<DataGrid ItemsSource="{Binding SelectedItem.Table}" /> 

Answer 1

从你的问题中有限的信息，我猜你的数据表中包含了我不推荐，因为它会让你的代码，以便更复杂的自定义类型的列。但是，如果你决定这样做，你可以实现自定义列类型来处理。我还没有尝试过，但这个链接看起来很有希望：Bind DataTable to WPF DataGrid using DataGridTemplateColumn Programatically

您也可以使用值转换器来实现相同的目的。下面的示例传递列索引作为参数，但您也可以使用某种格式（例如0值，意思是第0列，属性值）传递您感兴趣的属性。

XAML：

<Window x:Class="GridCellDemo.Window1" 
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" 
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" 
    xmlns:Controls="clr-namespace:Microsoft.Windows.Controls;assembly=WPFToolkit" 
    xmlns:GridCellDemo="clr-namespace:GridCellDemo" 
    Title="Window1" Height="300" Width="300"> 

    <Window.Resources> 
     <GridCellDemo:CellConverter x:Key="CellConverter" /> 
    </Window.Resources> 

    <Grid> 
     <Controls:DataGrid ItemsSource="{Binding Data}" AutoGenerateColumns="False"> 
      <Controls:DataGrid.Columns> 
       <Controls:DataGridTextColumn Header="Col 0" Binding="{Binding ., Converter={StaticResource CellConverter}, ConverterParameter=0}" /> 
       <Controls:DataGridTextColumn Header="Col 1" Binding="{Binding ., Converter={StaticResource CellConverter}, ConverterParameter=1}" /> 
      </Controls:DataGrid.Columns> 
     </Controls:DataGrid> 

    </Grid> 
</Window> 

后面的代码：

using System; 
using System.Data; 
using System.Windows; 
using System.Windows.Data; 

namespace GridCellDemo 
{ 
    public partial class Window1 : Window 
    { 
     public Window1() 
     { 
      InitializeComponent(); 

      DataContext = this; 
     } 

     public DataTable Data 
     { 
      get 
      { 
       DataTable dt = new DataTable(); 
       dt.Columns.Add(new DataColumn("Col0", typeof(GridCell))); 
       dt.Columns.Add(new DataColumn("Col1", typeof(GridCell))); 

       DataRow row0 = dt.NewRow(); 
       dt.Rows.Add(row0); 
       row0["Col0"] = new GridCell() { Value = "R0C0" }; 
       row0["Col1"] = new GridCell() { Value = "R0C1" }; 

       DataRow row1 = dt.NewRow(); 
       dt.Rows.Add(row1); 
       row1["Col0"] = new GridCell() { Value = "R1C0" }; 
       row1["Col1"] = new GridCell() { Value = "R1C1" }; 

       return dt; 
      } 
     } 
    } 

    public class GridCell 
    { 
     public string Value { get; set; } 
     public Guid Id { get; set; } 
    } 

    public class CellConverter : IValueConverter 
    { 
     public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture) 
     { 
      DataRowView drv = value as DataRowView; 
      if (drv == null) 
      { 
       return string.Empty; 
      } 
      int columnIndex = int.Parse(parameter.ToString()); 
      GridCell gridCell = drv[columnIndex] as GridCell; 
      return gridCell.Value; 
     } 

     public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture) 
     { 
      throw new NotImplementedException(); 
     } 
    } 
} 

Answer 2

尝试ItemsSource="{Binding Path=GridCellList}"。

<DataGrid ItemsSource="{Binding GridCellList}" AutoGenerateColumns="False"> 
    <DataGrid.Columns> 
     <DataGridTextColumn Header="Value" Binding="{Binding Path=Value}" /> 
     <DataGridTextColumn Header="Guid" Binding="{Binding Path=Guid}" /> 
    </DataGrid.Columns> 
</DataGrid>