需要从SQL查询中lambda表达式一些帮助

Question

我有这样的SQL查询：

select 
    SubCaseNumber, MySaleries.WorkDate, stscreator.name, Status, SheetId 
from 
    (select * 
    from 
     (select distinct 
       Sheets.SheetID SheetID, ShtInfos.SheetInfoID SheetInfoID, 
       ShtInfos.Creator_Id STSCreatorID, ShtUsers.User_ID STSFitterID, 
       Sheets.Status, ShtInfos.workdate, ShtInfos.SubCase_SubCaseId 
      from [Sheets] 
      left join [SheetInfoes] ShtInfos on sheets.SheetInfo_SheetInfoId = ShtInfos.SheetInfoId 
      left join [SheetUsers] ShtUsers on Sheets.SheetID = ShtUsers.Sheet_SheetID) AllSheets 
     where 
      (stsfitterID = '08153661-6520-4435-81e6-6064084db74d' 
      or stscreatorid = '08153661-6520-4435-81e6-6064084db74d') 
      and Status = 1) MySaleries 
join 
    [SubCases] SubCases on SubCase_SubCaseId = SubCases.SubCaseId 
join 
    [AspNetUsers] STSCreator on STSCreator.Id = MySaleries.STSCreatorID; 

（返回8行 - 正确）

我写了下面的LINQ查询来实现的LINQ的SQL ：

from Sht in Sheets 
join SI in SheetInfoes on Sht.SheetInfo_SheetInfoId equals SI.SheetInfoId 
join SC in SubCases on SI.SubCase_SubCaseId equals SC.SubCaseId 
join ShtUsr in SheetUsers on Sht.SheetId equals ShtUsr.Sheet_SheetId 
join STSUsr in AspNetUsers on SI.Creator_Id equals STSUsr.Id 
where (ShtUsr.User_Id == "08153661-6520-4435-81e6-6064084db74d" || SI.Creator_Id == "08153661-6520-4435-81e6-6064084db74d") && SI.Status == 1 
select new {SC.SubCaseNumber, SI.WorkDate, STSUsr.Name, Sht.Status, Sht.SheetId} 

返回50行 - 也应该蜂8行。

我有以下表格：

[SheetInfoes], [Sheets], [SubCases], [AspNetUsers], [SheetUsers] 

我在做什么错？

Answer 1

您发布的SQL中的连接条件是LEFT连接。你在代码中的连接只是没有任何过滤的连接。

例子：

from maintable in Repo.T_Whatever 
from xxx in Repo.T_ANY_TABLE.Where(join condition).DefaultIfEmpty() 

我设置它是这样的：

var query = (
from Sht in Sheets 
from SheetInfoes 
    .where(x => x.SheetInfoId == Sht.SheetInfo_SheetInfoId) 
    .DefaultIfEmpty() // <== left join 
from ShtUsr in SheetUsers 
    .where(x => x.SheetId == ShtUsr.Sheet_SheetId) 
    .DefaultIfEmpty() // <== left join 
//You'll need to finish it 

看看本作的详细信息：Left Outer Joins