以编程方式在java中构建JSON

Question

我需要以编程方式构建以下JSON。但是，需要一种优雅的方式将Java对象转换为JSON。所以，我可以避免字符串生成器来构建下面的JSON。

我意识到，有时候，我对在构建JSON的特定关键的参数数组。 请分享解决该问题的通用方法。

请分享一些想法了这一点。

{ 
    "tropo": [ 
     { 
      "ask": { 
       "attempts": 3, 
       "say": [ 
        { 
         "value": "Hi.", 
         "event": "timeout" 
        }, 
        { 
         "value": "Hello", 
         "event": "nomatch:1" 
        }, 
        { 
         "value": "Hello2", 
         "event": "nomatch:2" 
        }, 
        { 
         "value": "Satheesh", 
         "voice": "veronica" 
        } 
       ], 
       "choices": { 
        "value": "Yes(1,Yes),No(2,No)", 
        "mode": "ANY" 
       }, 
       "voice": "veronica", 
       "recognizer": "en-us", 
       "timeout": 8, 
       "name": "year", 
       "minConfidence": 39, 
       "required": true 
      } 
     }, 
     { 
      "on": { 
       "next": "https://test.app.com/WAP2/", 
       "event": "continue" 
      } 
     }, 
     { 
      "on": { 
       "next": "https://test.app.com/WAP2/", 
       "event": "incomplete" 
      } 
     }, 
     { 
      "on": { 
       "next": "", 
       "event": "hangup" 
      } 
     } 
    ] 
} 

Answer 1

正如paulsm4所说，我会看看gson。它很容易使用，你可以找到很多关于网络如何工作的例子（official user guide）。

例子：

Employee employee = new Employee(); 
employee.setId(1); 
employee.setFirstName("Lokesh"); 
employee.setLastName("Gupta"); 
employee.setRoles(Arrays.asList("ADMIN", "MANAGER")); 

Gson gson = new Gson(); 

System.out.println(gson.toJson(employee)); 

Output: 

{"id":1,"firstName":"Lokesh","lastName":"Gupta","roles":["ADMIN","MANAGER"]} 

从howtodoinjava.com/的谷歌GSON教程：从JSON转换Java对象/。