1
我有一个iphone应用程序,我在做推送通知作为alertview.When我的应用程序处于后台状态时,推送通知即将到来,当我点击它或解锁手机时,它直接进入应用程序,我已经离开它在forground状态。我在警报中添加一个动作,点击查看按钮,它将去往另一个视图控制器。我不想进入应用程序,当我点击通知。我需要显示alertview和视图按钮点击,当我需要做我的action.Can人帮助我实现this.This是我的代码片段` -推送通知警报视图操作?
- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{
//check application in forground or background
if(application.applicationState == UIApplicationStateActive)
{
//NSLog(@"FOreGround");
//NSLog(@"and Showing %@",userInfo)
}
else
{
NSDictionary *curDict= [userInfo objectForKey:@"aps"];
UIAlertView *connectionAlert = [[UIAlertView alloc] initWithTitle:@"app" message:[NSString stringWithFormat:@"%@",[curDict objectForKey:@"alert"]] delegate:self cancelButtonTitle:@"View" otherButtonTitles:@"Cancel",nil];
[connectionAlert show];
[connectionAlert release];
[UIApplication sharedApplication].applicationIconBadgeNumber =[[curDict objectForKey:@"badge"] intValue];
}
}
- (void)applicationWillEnterForeground:(UIApplication *)application
{
NSLog(@"applicationWillEnterForeground");
[UIApplication sharedApplication].applicationIconBadgeNumber = 0;
}
- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
NSString *title = [alertView buttonTitleAtIndex:buttonIndex];
if ([title isEqualToString:@"View"])
{
NSArray *mycontrollers = self.tabBarController.viewControllers;
NSLog(@"%@",mycontrollers);
[[mycontrollers objectAtIndex:0] popToRootViewControllerAnimated:NO];
mycontrollers = nil;
tabBarController.selectedIndex = 0;
}
}
很抱歉,但你能更准确?触摸通知时,您不想进入该应用程序?这根本不可能...... – Yorxxx 2012-07-19 08:49:52