Neo4jClient - 如何获取节点？

我正在试用Neo4jClient为Neo4j图形数据库，使用发现的示例here。Neo4jClient - 如何获取节点？

在下面很简单的代码：

var client = new GraphClient(new Uri("http://localhost:7474/db/data")); 
client.Connect(); 

var myNodeReference = client.Create(new MyNode { Foo = "bar" }); 
var myNode = client.Get<MyNode>(myNodeReference);

在最后一行（.Get）以下错误被抛出：

An item with the same key has already been added.

（同样的错误被抛出，即使Get是第一个也是唯一的方法，我使用之前创建的一些现有密钥来获取节点）。

看着堆栈跟踪后，我发现，它涉及到Neo4jClient，而不是Neo4j的分贝，因为它似乎是添加到字典时所引发的错误：

at System.ThrowHelper.ThrowArgumentException(ExceptionResource resource) 
    at System.Collections.Generic.Dictionary`2.Insert(TKey key, TValue value, Boolean add) 
    at System.Linq.Enumerable.ToDictionary[TSource,TKey,TElement](IEnumerable`1 source, Func`2 keySelector, Func`2 elementSelector, IEqualityComparer`1 comparer) 
    at System.Linq.Enumerable.ToDictionary[TSource,TKey,TElement](IEnumerable`1 source, Func`2 keySelector, Func`2 elementSelector) 
    at Neo4jClient.Deserializer.CommonDeserializerMethods.GetPropertiesForType(Type objType) in c:\TeamCity\buildAgent\work\460e89b30f53245b\Neo4jClient\Deserializer\CommonDeserializerMethods.cs:line 344 
    at Neo4jClient.Deserializer.CommonDeserializerMethods.Map(Object targetObject, JToken parentJsonToken, CultureInfo culture, IEnumerable`1 typeMappings, Int32 nestingLevel) in c:\TeamCity\buildAgent\work\460e89b30f53245b\Neo4jClient\Deserializer\CommonDeserializerMethods.cs:line 228 
    at Neo4jClient.Deserializer.CommonDeserializerMethods.CreateAndMap(Type type, JToken element, CultureInfo culture, IEnumerable`1 typeMappings, Int32 nestingLevel) in c:\TeamCity\buildAgent\work\460e89b30f53245b\Neo4jClient\Deserializer\CommonDeserializerMethods.cs:line 210 
    at Neo4jClient.Deserializer.CommonDeserializerMethods.SetPropertyValue(Object targetObject, PropertyInfo propertyInfo, JToken value, CultureInfo culture, IEnumerable`1 typeMappings, Int32 nestingLevel) in c:\TeamCity\buildAgent\work\460e89b30f53245b\Neo4jClient\Deserializer\CommonDeserializerMethods.cs:line 132 
    at Neo4jClient.Deserializer.CommonDeserializerMethods.Map(Object targetObject, JToken parentJsonToken, CultureInfo culture, IEnumerable`1 typeMappings, Int32 nestingLevel) in c:\TeamCity\buildAgent\work\460e89b30f53245b\Neo4jClient\Deserializer\CommonDeserializerMethods.cs:line 234 
    at Neo4jClient.Deserializer.CustomJsonDeserializer.Deserialize[T](RestResponse response) in c:\TeamCity\buildAgent\work\460e89b30f53245b\Neo4jClient\Deserializer\CustomJsonDeserializer.cs:line 59 
    at RestSharp.RestClient.Deserialize[T](IRestRequest request, RestResponse raw)

如果相关，这些都是从NuGet包版本：
<package id="Neo4jClient" version="1.0.0.397" targetFramework="net40-Client" />
<package id="Newtonsoft.Json" version="4.0.8" targetFramework="net40-Client" />
<package id="RestSharp" version="102.7" targetFramework="net40-Client" />

我在这里做错了什么？

编辑MyNode类：

[JsonObject] 
public class MyNode 
{ 
    [JsonProperty("Bar")] 
    public string Foo { get; set; } 

    [JsonIgnore] 
    public string Bar { get; set; } 
}

来源

2012-07-24 veljkoz

你能分享你的'MyNode'类吗？ – 2012-07-25 10:36:20

更新 - 在帖子末尾添加了... – veljkoz 2012-07-25 14:05:07

除非你真的需要做到这一点，我会脱下[JsonProperty("Bar")]位，因为这是什么原因造成的麻烦。解串器无法区分实际属性'Bar'和JsonProperty'Bar'

如果你把它关掉，你的代码将会正常工作。

如果你想向使用JSON东西，你可以创建另一个Node对象：

public class OtherNode { public string Bar { get;set;} }

和deserialise成：

var nodeReference = client.Create(new MyNode { Foo = "blah" }); 
var retrieved = client.Get<OtherNode>(nodereference);

，这将正常工作。

来源

2012-07-25 14:47:06

yeap，就这么简单;）谢谢 – veljkoz 2012-07-25 18:57:33

Neo4jClient - 如何获取节点？

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