在不同阵列

Question

我有一个foreach语法比较不同的项目，其产生以下结果：

array 
    0 => 
    array 
     'value' => string '2012-05-09T12:00:00' (length=19) 
     'value2' => string '2012-05-09T15:00:00' (length=19) 
     'timezone' => string 'Europe/Paris' (length=12) 
     'timezone_db' => string 'UTC' (length=3) 
     'date_type' => string 'date' (length=4) 
    1 => 
    array 
     'value' => string '2012-03-14T13:00:00' (length=19) 
     'value2' => string '2012-03-14T16:00:00' (length=19) 
     'timezone' => string 'Europe/Paris' (length=12) 
     'timezone_db' => string 'UTC' (length=3) 
     'date_type' => string 'date' (length=4) 
    2 => 
    array 
     ... 
array 
    0 => 
    array 
     'value' => string '2012-02-08T13:00:00' (length=19) 
     'value2' => string '2012-02-08T16:00:00' (length=19) 
     'timezone' => string 'Europe/Paris' (length=12) 
     'timezone_db' => string 'UTC' (length=3) 
     'date_type' => string 'date' (length=4) 
    1 => 
    array 
     'value' => string '2012-03-14T13:00:00' (length=19) 
     'value2' => string '2012-03-14T16:00:00' (length=19) 
     'timezone' => string 'Europe/Paris' (length=12) 
     'timezone_db' => string 'UTC' (length=3) 
     'date_type' => string 'date' (length=4) 
    2 => 
    array 
     ... 

的...代表更大量的代码，全部采用相同的结构。

这里是php代码：

foreach ($result as $term) { 
    $node = node_load($term->nid); 
    $dates = $node->field_date['und']; 
    var_dump($dates); 
} 

目标是比较的结果，并检查他们的任何不平等。那么，我的目标是一个脚本，让我从第一阵列和第二阵列$dates[0]['value']比较$dates[0]['value'] ...

我想所有的0项目或全部1项目组成新阵列后来检查他们，但迄今没有运气。有人有另一个想法吗？

Answer 1

$array[] = array(
    'value'  => '2012-03-14T13:00:00', 
    'value2'  => '2012-03-14T16:00:00',  // <--- Error 
    'timezone' => 'Europe/Paris', 
    'timezone_db' => 'UTC', 
    'date_type' => 'date', 
); 
$array[] = array(
    'value'  => '2012-03-14T13:00:00a',  // <--- Error 
    'value2'  => '2012-03-14T16:00:00', 
    'timezone' => 'Europe/Paris', 
    'timezone_db' => 'UTC', 
    'date_type' => 'date', 
); 
$array[] = array(
    'value'  => '2012-03-14T13:00:00', 
    'value2'  => '2012-03-14T16:00:00tt', // <--- Error 
    'timezone' => 'Europe/Paris', 
    'timezone_db' => 'UTC', 
    'date_type' => 'date11', 
); 

$errors = array(); 
for($i=0; $i < count($array)-1; $i++) 
    $errors = array_merge(array_diff_assoc($array[$i], $array[$i+1])); 

var_dump($errors); 

/* Output 
* ------ 
* Array 
* (
*  [value] => 2012-03-14T13:00:00a 
*  [value2] => 2012-03-14T16:00:00 
*  [date_type] => date 
*) 
*/ 

Answer 2

$array = array(); 

$array[] = array(
    'value'  => '2012-03-14T13:00:00', 
    'value2'  => '2012-03-14T16:00:00', 
    'timezone' => 'Europe/Paris', 
    'timezone_db' => 'UTC', 
    'date_type' => 'date', 
); 
$array[] = array(
    'value'  => '2012-03-14T13:00:00', 
    'value2'  => '2012-03-14T16:00:00dddd',  // <--- Error is here 
    'timezone' => 'Europe/Paris', 
    'timezone_db' => 'UTC', 
    'date_type' => 'date', 
); 
$array[] = array(
    'value'  => '2012-03-14T13:00:00', 
    'value2'  => '2012-03-14T16:00:00', 
    'timezone' => 'Europe/Paris', 
    'timezone_db' => 'UTC', 
    'date_type' => 'date', 
); 

if(count($array) > 1) 
{ 
    $error = false; 
    $keyCount = count($array); 

    for($i=0; $i < $keyCount-1; $i++) 
    { 
     foreach($array[$i] as $key=>$val) 
     { 
      if($array[$i+1][$key] != $val) 
      { 
       $error = $key; 
       break; 
      } 
     } 
    } 
} 

if($error) 
    echo "Error key = " . $error; 
else 
    echo "No errors"; 

输出：Error key = value2

编辑：改变以反映问题的新认识。

Answer 3

我觉得这是一种

$array1 = array('marko','aca','milos'); 
$array2 = array('nemanja','marko','milos'); 
for($i=0;$i<count($array2);$i++)//count any array 
{ 
if($array1[$i]!=$array2[$i]) 
{ 
    echo "Error in ".$i." <br/>";/*it will show you a number of part of array wich don't match */ 
} 
} 

这会给
错误在0
错误1个