我有以下的风格,但我需要让编程:如何设置样式编程
<xcdg:DataGridControl MinHeight="300"
Name="listViewUnallocated"
ItemsSource="{Binding Source={StaticResource
cvs_unallocatedTerminals}}"
AllowDrop="True"
Drop="Grid_Drop"
MouseMove="Grid_MouseMove"
KeyUp="listViewUnallocated_KeyUp"
MouseDoubleClick="gridUnallocated_MouseDoubleClick"
ReadOnly="True"
DockPanel.Dock="Top">
<xcdg:DataGridControl.Resources>
<Style TargetType="{x:Type xcdg:DataRow}" x:Name="selectedStyleTrigger">
<Style.Triggers>
<DataTrigger Binding="{Binding TerminalId}" Value="72948028">
<Setter Property="Background" Value="Red" />
</DataTrigger>
</Style.Triggers>
</Style>
</xcdg:DataGridControl.Resources>
FindResource(“ResourceName”)和Resources [“ResourceName”]之间有什么区别? – SepehrM 2014-09-03 11:23:25
有了这个,我无法在Window的构造函数中找到样式,但是可以使用'FindResource'方法。 (这是一个抽象类,在几个地方继承,没有定义XAML。) – ANeves 2015-01-08 19:24:41