2011-09-26 97 views
18

与我发表的另一篇文章类似,这回答了该帖子并创建了一个新问题。创建数据库连接并维护多个进程(多处理)

回顾:我需要更新空间数据库中的每个记录,其中有一组覆盖多边形数据集的点的数据集。对于每个点要素,我想分配一个键以将其与它所在的面要素关联起来。因此,如果我的观点'纽约市'位于美国多边形和美国多边形'GID = 1'内,我将为我的观点纽约市分配'gid_fkey = 1'。

好吧,这已经实现了使用多处理。我注意到使用这个速度增加了150%,所以它工作。但我认为有一些不必要的开销,因为每个记录需要一个数据库连接。

所以这里是代码:

import multiprocessing, time, psycopg2 

class Consumer(multiprocessing.Process): 

    def __init__(self, task_queue, result_queue): 
     multiprocessing.Process.__init__(self) 
     self.task_queue = task_queue 
     self.result_queue = result_queue 

    def run(self): 
     proc_name = self.name 
     while True: 
      next_task = self.task_queue.get() 
      if next_task is None: 
       print 'Tasks Complete' 
       self.task_queue.task_done() 
       break    
      answer = next_task() 
      self.task_queue.task_done() 
      self.result_queue.put(answer) 
     return 


class Task(object): 
    def __init__(self, a): 
     self.a = a 

    def __call__(self):   
     pyConn = psycopg2.connect("dbname='geobase_1' host = 'localhost'") 
     pyConn.set_isolation_level(0) 
     pyCursor1 = pyConn.cursor() 

     procQuery = 'UPDATE city SET gid_fkey = gid FROM country WHERE ST_within((SELECT the_geom FROM city WHERE city_id = %s), country.the_geom) AND city_id = %s' % (self.a, self.a) 

     pyCursor1.execute(procQuery) 
     print 'What is self?' 
     print self.a 

     return self.a 

    def __str__(self): 
     return 'ARC' 
    def run(self): 
     print 'IN' 

if __name__ == '__main__': 
    tasks = multiprocessing.JoinableQueue() 
    results = multiprocessing.Queue() 

    num_consumers = multiprocessing.cpu_count() * 2 
    consumers = [Consumer(tasks, results) for i in xrange(num_consumers)] 
    for w in consumers: 
     w.start() 

    pyConnX = psycopg2.connect("dbname='geobase_1' host = 'localhost'") 
    pyConnX.set_isolation_level(0) 
    pyCursorX = pyConnX.cursor() 

    pyCursorX.execute('SELECT count(*) FROM cities WHERE gid_fkey IS NULL')  
    temp = pyCursorX.fetchall()  
    num_job = temp[0] 
    num_jobs = num_job[0] 

    pyCursorX.execute('SELECT city_id FROM city WHERE gid_fkey IS NULL')  
    cityIdListTuple = pyCursorX.fetchall()  

    cityIdListList = [] 

    for x in cityIdListTuple: 
     cityIdList.append(x[0]) 


    for i in xrange(num_jobs): 
     tasks.put(Task(cityIdList[i - 1])) 

    for i in xrange(num_consumers): 
     tasks.put(None) 

    while num_jobs: 
     result = results.get() 
     print result 
     num_jobs -= 1 

它看起来是每个连接0.3和1.5秒之间,因为我有“时间”模块测量。

有没有办法让每个进程都建立一个数据库连接,然后只用city_id info作为一个变量,我可以将这个变量提供给这个open中的游标查询?这样我说四个进程与每个数据库连接,然后放下我city_id以某种方式处理。

回答

31

尝试隔离在消费者构造你的连接的创建,然后把它交给执行任务:

import multiprocessing, time, psycopg2 

class Consumer(multiprocessing.Process): 

    def __init__(self, task_queue, result_queue): 
     multiprocessing.Process.__init__(self) 
     self.task_queue = task_queue 
     self.result_queue = result_queue 
     self.pyConn = psycopg2.connect("dbname='geobase_1' host = 'localhost'") 
     self.pyConn.set_isolation_level(0) 


    def run(self): 
     proc_name = self.name 
     while True: 
      next_task = self.task_queue.get() 
      if next_task is None: 
       print 'Tasks Complete' 
       self.task_queue.task_done() 
       break    
      answer = next_task(connection=self.pyConn) 
      self.task_queue.task_done() 
      self.result_queue.put(answer) 
     return 


class Task(object): 
    def __init__(self, a): 
     self.a = a 

    def __call__(self, connection=None):   
     pyConn = connection 
     pyCursor1 = pyConn.cursor() 

     procQuery = 'UPDATE city SET gid_fkey = gid FROM country WHERE ST_within((SELECT the_geom FROM city WHERE city_id = %s), country.the_geom) AND city_id = %s' % (self.a, self.a) 

     pyCursor1.execute(procQuery) 
     print 'What is self?' 
     print self.a 

     return self.a 

    def __str__(self): 
     return 'ARC' 
    def run(self): 
     print 'IN' 
+1

伴侣得到成功的治疗。没有荣誉给你批准的机会,但代码是绝对的魔法。摆脱固定的数据库连接可以轻松地将速度提高50%。在某些情况下可能接近100%。再次感谢。 –

+0

@EnE_:我很高兴它帮助你:)。你应该接受答案,你有权这样做,因为你是问题的主人。 –

+0

好吧,我不得不承认,我认为我应该按下向上的箭头而不是剔。 '批准的滴答声'是一个不幸的自我谴责的转向= D –