2009-11-12 63 views
0

我有这两个表:课程(PK CourseId,Title)和参加者(PK AttendeeId,FK CourseId,方法)。
许多与会者可以通过6种方法中的任何一种来进行给定的课程。计算SQL Server 2005中的统计模式

如何在课程表(CourseId,Title)中为每个课程的所有参加者使用Method的统计模式打印出每个课程的一条记录?

+1

给例子中,你需要输出的数据。 – 2009-11-12 07:03:08

回答

2

好的,根据我的理解你需要。

从这Mode (statistics)

模式不一定是唯一的,因为 相同的最大频率可以 为不同的值来实现。

所以这里去

DECLARE @Course TABLE(
     CourseID INT, 
     Title VARCHAR(50) 
) 

INSERT INTO @Course (CourseID,Title) SELECT 1, 'AA' 
INSERT INTO @Course (CourseID,Title) SELECT 2, 'BB' 
INSERT INTO @Course (CourseID,Title) SELECT 3, 'CC' 

DECLARE @Attendee TABLE(
     AttendeeID INT, 
     CourseID INT, 
     Method INT 
) 

INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 1, 1, 1 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 2, 1, 1 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 3, 1, 2 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 4, 1, 1 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 5, 1, 3 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 6, 1, 3 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 7, 1, 4 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 8, 1, 4 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 9, 1, 5 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 10, 1, 6 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 11, 1, 6 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 12, 1, 6 

INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 13, 2, 1 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 14, 2, 3 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 15, 2, 3 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 16, 2, 3 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 17, 2, 3 
INSERT INTO @Attendee (AttendeeID,CourseID,Method) SELECT 18, 2, 6 

DECLARE @Counts TABLE(
     CourseID INT, 
     Title VARCHAR(50), 
     Method INT, 
     NumberMethodPerCourse INT 
) 

INSERT INTO @Counts (CourseID,Title,Method,NumberMethodPerCourse) 
SELECT c.CourseID, 
     c.Title, 
     a.Method, 
     COUNT(a.Method) NumberMethodPerCourse 
FROM @Course c INNER JOIN 
     @Attendee a ON c.CourseID = a.CourseID 
GROUP BY c.CourseID, 
      c.Title, 
      a.Method 

SELECT CourseMax.CourseID, 
     CourseMax.Title, 
     CourseMax.MaxNumber, 
     Counts.Method 
FROM (
      SELECT Counts.CourseID, 
        Counts.Title, 
        MAX(NumberMethodPerCourse) MaxNumber 
      FROM @Counts Counts 
      GROUP BY Counts.CourseID, 
         Counts.Title 
     ) CourseMax INNER JOIN 
     @Counts Counts ON CourseMax.CourseID = Counts.CourseID 
         AND CourseMax.MaxNumber = Counts.NumberMethodPerCourse 
+0

完美!正是我需要的。只是为了满足我的需要而在附加的条款中加入了我很高兴。我试图在没有表的一个查询中执行它(不太好)。谢谢。 – DancesWithBamboo 2009-11-12 07:57:19

+0

您可以在没有桌子的情况下做到这一点,但它会变得杂乱无章) – 2009-11-12 07:58:32