SQL Server查询组由项目

Question

我有3列的表，SQL Server 2008中

item, count , date 

我想作为与具有格式2011 日期colums选择每个项目的总数为当天查询-03-30 09：00：00.000

select 
    date,item, sum(count) as total 
from 
    table1 
group by 
    date,item 

编辑：

select item, dateadd(day,datediff(day,0,date),0) as dateInserted, sum(count) 
as total from Table1 group by item, dateadd(day,datediff(day,0,date),0) order by 1 

第一选择换货政... rns总计但按日期时间分组而不是日期...然后第二个返回总计正确，但我发现一些项目出现两次相同的日期，但不同的总数

Answer 1

听起来像你正在寻找'当前日'的结果？

select item, dateadd(day, datediff(day, 0, date), 0) as dateInserted, 
     sum(count) as total 
from Table1 
WHERE  
    dateadd(day, datediff(day, 0, [date]), 0) = 
    dateadd(day, datediff(day, 0, getdate()), 0) 
group by 
    item, dateadd(day, datediff(day, 0, date), 0) 
order by 1 

如果您使用SQL Server 2008中，使用DATE数据类型。

select item, 
     CAST([date] as DATE)) as dateInserted, 
     sum(count) as total 
from Table1 
WHERE  
    CAST([date] as DATE)) = CAST(getdate() as DATE) 
group by 
    item, CAST([date] as DATE)) 
order by 1