的Python - 跳过空行和打印3行的匹配后

Question

我似乎无法跳过空线 -

import re 

with open('list.txt', 'r+') as f: 
     line = f.readline() 
     while(line): 
     if line != ['']: 
      if " win" in line: 
       print(f.readline(),end="") 
      # 2nd line 
       print(f.readline(),end="") 
      # 3rd line 
       print(f.readline(),end="") 
      line = f.readline() 

LIST.TXT

You tell yourself... 
That should have been my big win. 

It's a kick in the gut. 
Knowing in your heart the reason. 
While you're stuck on the outside. 
Grinning. 

它打印中包含instead- 线在空行后出现。

It's a kick in the gut. Knowing in your heart the reason.

Answer 1

打印时，你需要告诉它跳过空白行（注释是内联）：

if " win" in line: 
    for _ in range(3): # do three times 
     line = f.readline() # get next line 
     # skip blank lines 
     while not line.strip(): 
      line = f.readline() 
     # Print the non-blank line 
     print(line, end="") 
line = f.readline()