CakePHP的2检索where条件取决于子表

Question

我有一个奇怪的行为，我不跟我的CakePHP的理解2. 在我的模型“研究”我有一个有很多关系数据：

class Study extends AppModel { 

public $hasOne = array(
    'SubjectFilter' => array(
     'className' => 'Subject_filter', 
     'dependent' => true 
    ) 

    ); 


public $hasMany = array(

    'ExecutedStudyTable' => array(
      'className' => 'ExecutedStudyTable', 
      'foreignKey' =>'study_id', 
      'dependent' => true, 
    ), 

); 

该ExecutedtStudyTable模式是这样的：

class ExecutedStudyTable extends AppModel { 

    public $belongsTo= array(
    'Study' => array(
     'className' => 'Study', 
     'foreignKey' => 'study_id' 
    ), 
    'User' => array(
     'className' => 'User', 
     'foreignKey' => false, 
     'conditions' => array('ExecutedStudyTable.user_id = User.id') 
    ) 

); 

} 检索数据一切正常，直到当我尝试这样做：

 $studies = $this -> Study -> find('all',array(
'conditions' => array(
      'Study.user_id' => $cId, 
      'OR'=>array(
       array('Study.state'=>'active'), 
       array('Study.state'=>'rehearsal') 
      ),     
      'SubjectFilter.studyCode'=>null, 
      'ExecutedStudyTable.user_id'=>$user 
) 
    )); 

我得到这个错误：Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'ExecutedStudyTable.user_id' in 'where clause'

CakePHP的建立此查询是这样的：

SELECT `Study`.`id`, `Study`.`user_id`, `Study`.`created`, `Study`.`modified`, `Study`.`started`, `Study`.`completed`, `Study`.`title`, `Study`.`description`, `Study`.`numberParticipants`, `Study`.`state`, `User`.`id`, `User`.`username`, `User`.`password`, `User`.`role`, `User`.`firstName`, `User`.`familyName`, `User`.`email`, `User`.`addressStreet`, `User`.`addressCity`, `User`.`addressZip`, `User`.`phone1`, `User`.`phone2`, `User`.`created`, `User`.`modified`, `User`.`passwordResetCode`, `User`.`passwordResetDate`, `User`.`sendUsernameDate`, `SubjectFilter`.`id`, `SubjectFilter`.`study_id`, `SubjectFilter`.`m`, `SubjectFilter`.`f`, `SubjectFilter`.`age18_24`, `SubjectFilter`.`age25_34`, `SubjectFilter`.`age35_44`, `SubjectFilter`.`age45_54`, `SubjectFilter`.`age55plus`, `SubjectFilter`.`studyCode` FROM `eyevido`.`studies` AS `Study` LEFT JOIN `eyevido`.`users` AS `User` ON (`Study`.`user_id` = `User`.`id`) LEFT JOIN `eyevido`.`subject_filters` AS `SubjectFilter` ON (`SubjectFilter`.`study_id` = `Study`.`id`) WHERE `Study`.`user_id` = 1402402538 AND ((`Study`.`state` = 'active') OR (`Study`.`state` = 'rehearsal')) AND `SubjectFilter`.`studyCode` IS NULL AND `ExecutedStudyTable`.`user_id` = 1130451831 

的ExecutedStudyTable没有加入像SubjectFilter并没有别名为表定义。为什么在hasOne关系上而不是在hasMany上正常工作？我在哪里犯错误？

我很欣赏你的答复

Answer 1

如果你想过滤由相关模型的领域模型，方法之一是Joining tables。

注意：为模型ExecutedStudyTable提及适当的表名称。还要提到两个表之间的连接条件。

$studies = $this->Study->find('all',array(
'fields' => array('Study.*'), 
'joins' => array(
     array('table' => 'executed_study_table', // Table name 
     'alias' => 'ExecutedStudyTable', 
     'type' => 'INNER', 
     'conditions' => array(
      'ExecutedStudyTable.<field name> = Study.<field>', // Mention join condition here 
     ) 
    ) 
), 
'conditions' => array(
     'Study.user_id' => $cId, 
     'OR'=>array(
      array('Study.state'=>'active'), 
      array('Study.state'=>'rehearsal') 
     ),     
     'SubjectFilter.studyCode' => null, 
     'ExecutedStudyTable.user_id' => $user 
), 
    'recursive' => -1 
));