Question

我在我的asp.net项目中有一个gridview，我使用的项目模板像;

<asp:TemplateField> 
        <ItemTemplate> 
         <asp:LinkButton ID = "lnkSil" runat="server" CommandName="bla" 
CommandArgument='<%# ((GridViewRow) Container).RowIndex %>' Text= "Sil" ></asp:LinkButton> 
        </ItemTemplate> 
        </asp:TemplateField> 

我想从后面的代码中看到这一点，我使用下面的代码;

((Button)e.Row.Cells[1].Controls[0]).Attributes.Add("onclick", "return confirm('Bu kaydi silmek istediginizden emin misiniz?')"); 

，但我失败了我如何能赶上落后于这个代码控制这样

还我试图

((LinkButton)e.Row.Cells[1].Controls[0]).Attributes.Add("onclick", "return confirm('Bu kaydi silmek istediginizden emin misiniz?')"); 

Answer 1

，如果你想获得访问事件，而不JavaScript的再使用GridView1_RowCommand。

protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e) 
{ 
    int currentRowIndex = Int32.Parse(e.CommandArgument.ToString()); 
    LinkButton bf = (LinkButton)gv.Rows[currentRowIndex].Cells[1].Controls[0]; 
    ... 
} 

Answer 2

试试这个..

protected void gvMyGrid_RowDataBound(object sender, System.Web.UI.WebControls.GridViewRowEventArgs e) 
{ 
if (e.Row.RowType == DataControlRowType.DataRow) { 
LinkButton lnkSil = (LinkButton)e.Row.FindControl("lnkSil"); 
lnkSil.Attributes.Add("onclick", "javascript:return confirm('Bu kaydi silmek istediginizden emin misiniz?');"); 
    } 
}