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我正在使用ransack进行搜索,现在我想在我的rails应用程序中实现分页。所以我使用了will_paginate gem。我面临的问题是,我无法弄清楚如何将paginate放入当前控制器代码中,因为它已根据查询获取结果。如何在rails中使用will_paginate和ransack
这里是我的控制器代码
def search
if params[:search].present? && params[:search].strip != ""
session[:loc_search] = params[:search]
end
arrResult = Array.new
if session[:loc_search] && session[:loc_search] != ""
@rooms_address = Room.where(active: true).near(session[:loc_search], 5, order: 'distance')
else
@rooms_address = Room.where(active: true).all
end
@search = @rooms_address.ransack(params[:q])
@rooms = @search.result
@arrRooms = @rooms.to_a
有人能告诉我如何把分页这里?
原木
18:29:40 web.1 | Room Load (0.8ms) SELECT rooms.*, 3958.755864232 * 2 * ASIN(SQRT(POWER(SIN((12.9715987 - rooms.latitude) * PI()/180/2), 2) + COS(12.9715987 * PI()/180) * COS(rooms.latitude * PI()/180) * POWER(SIN((77.5945627 - rooms.longitude) * PI()/180/2), 2))) AS distance, MOD(CAST((ATAN2(((rooms.longitude - 77.5945627)/57.2957795), ((rooms.latitude - 12.9715987)/57.2957795)) * 57.2957795) + 360 AS decimal), 360) AS bearing FROM "rooms" WHERE "rooms"."active" = $1 AND (rooms.latitude BETWEEN 12.754501025333727 AND 13.188696374666272 AND rooms.longitude BETWEEN 77.37177993269385 AND 77.81734546730614 AND (3958.755864232 * 2 * ASIN(SQRT(POWER(SIN((12.9715987 - rooms.latitude) * PI()/180/2), 2) + COS(12.9715987 * PI()/180) * COS(rooms.latitude * PI()/180) * POWER(SIN((77.5945627 - rooms.longitude) * PI()/180/2), 2)))) BETWEEN 0.0 AND 15) ORDER BY distance LIMIT 5 OFFSET 5 [["active", "t"]]
18:29:40 web.1 | (0.3ms) SELECT COUNT(*) FROM "rooms" WHERE "rooms"."active" = $1 AND (rooms.latitude BETWEEN 12.754501025333727 AND 13.188696374666272 AND rooms.longitude BETWEEN 77.37177993269385 AND 77.81734546730614 AND (3958.755864232 * 2 * ASIN(SQRT(POWER(SIN((12.9715987 - rooms.latitude) * PI()/180/2), 2) + COS(12.9715987 * PI()/180) * COS(rooms.latitude * PI()/180) * POWER(SIN((77.5945627 - rooms.longitude) * PI()/180/2), 2)))) BETWEEN 0.0 AND 15) [["active", "t"]]
感谢它的工作..但不是最好先分页或...在这种情况下这是最好的办法? – Abhilash
不是真的 - ransack也可以做排序,而不仅仅是搜索,而且你通常不希望只排序结果的当前页面。 – eugen
因此在使用ransack的时候使用willpaginate是一件矫枉过正的事情? – Abhilash