我使用different question thread中给出的答案中的代码,该代码根据表名创建序列和触发器。基于表名的Concatinate SEQUENCE/TRIGGER名称
不过,我有一个非常接近exceededing(或已经到达),30个字符的限制表中,所以我得到这个错误:
Error report:
ORA-00972: identifier is too long
ORA-06512: at line 15
00972. 00000 - "identifier is too long"
*Cause: An identifier with more than 30 characters was specified.
*Action: Specify at most 30 characters.
我的问题是,我该如何Concat的表名这样他们不会抛出这个错误,仍然保留标题中的一些表名称?也许concat到20个字符和最后的“_SEQ”或“_TRIG”?
这里是我的代码:
DECLARE
CURSOR TABLES
IS
SELECT *
FROM USER_TABLES
WHERE 0 =
(SELECT COUNT(*)
FROM USER_CONSTRAINTS
WHERE USER_CONSTRAINTS.TABLE_NAME = USER_TABLES.TABLE_NAME
AND USER_CONSTRAINTS.CONSTRAINT_TYPE = 'P'
);
BEGIN
FOR T IN TABLES
LOOP
EXECUTE IMMEDIATE 'CREATE SEQUENCE '||T.TABLE_NAME||'_SEQ START WITH 1';
EXECUTE IMMEDIATE 'UPDATE '||T.TABLE_NAME||' SET ID = '||T.TABLE_NAME||'Seq.NEXTVAL';
EXECUTE IMMEDIATE 'ALTER TABLE '||T.TABLE_NAME||' ADD PRIMARY KEY (ID)';
EXECUTE IMMEDIATE 'CREATE OR REPLACE TRIGGER '||T.TABLE_NAME||'_TRIG '||CHR(10) ||'BEFORE INSERT ON '||T.TABLE_NAME||' '||CHR(10) ||'FOR EACH ROW '||CHR(10) ||'BEGIN '||CHR(10) ||':NEW.ID := '||T.TABLE_NAME||'Seq.NEXTVAL; '||CHR(10) ||'END; ';
END LOOP;
END;
/
难道你不能简单地使用一个SUBSTR来修改表名称,比如25个字符,然后concat'_SEQ'或'_TRIG'? – Aleksej