我是java中的新成员,我得到了阿姆斯特朗数字的分配。 我已经创造了新的类ArmstrongNumber.java,我从本网站初始化方法:http://www.programmingsimplified.com/java/source-code/java-program-armstrong-numberJAVA如何返回间隔[100; 999]
现在,在其中的主要方法我创造了另一个方法的类在那里我打电话ArmstrongNumber类,现在我要回到阿姆斯特朗数间隔从[100至999]。
有我现在卡在哪里。
public static void armtrongNumbs()
{
ArmstrongNumber returnObj = new ArmstrongNumber(); // here i m calling class.
int start = 100;
int end = 999;
for(int i = start; i<= end; i++)
{
number = i + number;
returnObj.Armstrong(number);
}
//returnObj.Armstrong();
}
我的循环怎么会只返回阿姆斯特朗数?
编辑:ArmstrongNumber类
class ArmstrongNumber
{
public void Armstrong(int number)
{
int n, sum = 0, temp, remainder, digits = 0;
Scanner in = new Scanner(System.in);
System.out.println("Input a number to check if it is an Armstrong number");
n = in.nextInt();
temp = n;
// Count number of digits
while (temp != 0) {
digits++;
temp = temp/10;
}
temp = n;
while (temp != 0) {
remainder = temp%10;
sum = sum + power(remainder, digits);
temp = temp/10;
}
if (n == sum)
System.out.println(n + " is an Armstrong number.");
else
System.out.println(n + " is not an Armstrong number.");
}
static int power(int n, int r) {
int c, p = 1;
for (c = 1; c <= r; c++)
p = p*n;
return p;
}
}
什么returnObj? –
@ParaSara这是新创建的对象,我打电话给ArmstrongNumber类,我初始化armostring算法。 – BinaryTie
ok,returnObj.Armstrong(number)返回true或false,对不对? –