你可以有。您可以通过使用类似于下面的代码来继承字典,添加密钥查找(甚至保留名称字典)。然而,{...}
表单仍将使用内置的dict类(现在称为orig_dict),因此您必须将其括起来,如下所示:Dict({...})
。这个实现递归地将字典转换为新的形式,所以你不必使用上面的方法来处理任何普通字典本身的字典条目。
orig_dict = dict
class Dict(orig_dict):
def __init__(self, *args, **kwargs):
super(Dict, self).__init__(*args, **kwargs)
for k, v in self.iteritems():
if type(v) == orig_dict and not isinstance(v, Dict):
super(Dict, self).__setitem__(k, Dict(v))
def __getattribute__(self, k):
try: return super(Dict, self).__getattribute__(k)
except: return self.__getitem__(k)
def __setattr__(self, k, v):
if self.has_key(k): self.__setitem__(k, v)
else: return super(Dict, self).__setattr__(k, v)
def __delattr__(self, k):
try: self.__delitem__(k)
except: super(Dict, self).__delattr__(k)
def __setitem__(self, k, v):
toconvert = type(v) == orig_dict and not isinstance(v, Dict)
super(Dict, self).__setitem__(k, Dict(v) if toconvert else v)
# dict = Dict <-- you can even do this but I advise against it
# testing:
b = Dict(a=1, b=Dict(c=2, d=3))
c = Dict({'a': 1, 'b': {'c': 2, 'd': 3}})
d = Dict(a=1, b={'c': 2, 'd': {'e': 3, 'f': {'g': 4}}})
b.a = b.b
b.b = 1
d.b.d.f.g = 40
del d.b.d.e
d.b.c += d.b.d.f.g
c.b.c += c.a
del c.a
print b
print c
print d
来源
2012-02-17 03:46:53
Frg
你在寻找语法糖('mydict.root.secondary.user2')还是只通过字符串查找? – 2012-02-16 23:40:44