萨姆数组表

Question

我能够与代码打印阵列的列表在2D见下表

#include <iostream> 
#include <vector> 
using namespace std; 

void inputRoutine(vector<int> &a) 
{ 
    const int MAXNUM = 17; 
    for (int i = 1; i <= MAXNUM; i++) a.push_back(i); 
} 


void printRoutine(vector<int> a) 
{ 
    const int COLS = 5; 
    int size = a.size();           
    int fullrows = size/COLS;         
    int leftover = size % COLS;         
    int rows = fullrows + (leftover != 0);      

    cout << "TABLE:\n"; 
    for (int i = 0; i < rows; i++)        
    { 
     int indexTop = 0;           
     for (int j = 0; j < COLS; j++) 
     { 
     int index = indexTop + i;        
     if (i < fullrows || j < leftover) cout << a[index]; 
     cout << '\t';           
     if (j < leftover) indexTop += rows;     top-of-column 1-d index for the number in this column 
     else    indexTop += fullrows;    
     } 
     cout << '\n'; 
    } 
} 


int main() 
{ 
    vector<int> a; 
    inputRoutine(a); 
    printRoutine(a); 
} 

和我能够产生低于

TABLE: 1 5 9 12 15 
     2 6 10 13 16 
     3 7 11 14 17 
     4 8 

输出作为现在我想要得到打印表格的总和如下 （第一个数字是列号，第一行的第5列表示单独的行总数42,47,52,12，如表中所给出的，第二行列号1：如果只有1列，那么有17行 - 它应该是亲达斯总数）

C ROW SUMS 

5 42 47 52 12 
************************************ 
1 153 
************************t*********** 
2 11 13 15 17 19 21 23 25 9 
************************************ 

如何做到这一点，可以有人帮助。

Answer 1

我会这样做的方式，将有一个缓冲区row_sum这是这种情况下填充（和计算）打印表时。 打印完表格后，row_sum包含计算的行数总和。您可以将COLs设为printRoutine的参数，以便可以在不重新编译的情况下运行不同的COLS值。

Here是您原始代码的简单扩展，运行COLS = 1,...,5。对于每个值COLS它都会打印表格和行数。

#include <iostream> 
#include <vector> 
#include <numeric> 
using namespace std; 

void inputRoutine(vector<int> &a) 
{ 
    const int MAXNUM = 17; 
    for (int i = 1; i <= MAXNUM; i++) a.push_back(i); 
} 

void printRoutine(int COLS, vector<int> a, vector<int>& row_sum) 
{ 
    int size = a.size();           
    int fullrows = size/COLS;         
    int leftover = size % COLS;         
    int rows = fullrows + (leftover != 0);      

    // Set the size of the row_sum buffer 
    row_sum.resize(rows); 

    cout << "TABLE:\n"; 
    for (int i = 0; i < rows; i++)        
    { 
     int indexTop = 0;           
     for (int j = 0; j < COLS; j++) 
     { 
     int index = indexTop + i;        
     if (i < fullrows || j < leftover) 
     { 
      cout << a[index]; 

      // Add the value to the row sum. We do the add here, since 
      // if it should be printed it should also be added 
      row_sum[i] += a[index]; 
     } 
     cout << '\t';           
     if (j < leftover) indexTop += rows; // top-of-column 1-d index for the number in this column 
     else    indexTop += fullrows;    
     } 
     cout << '\n'; 
    } 

    // Special case for COLS == 1 
    if (COLS == 1) 
    { 
     row_sum[0] = std::accumulate(std::begin(row_sum), std::end(row_sum), 0); 
     row_sum.resize(1); 
    } 
} 

int main() 
{ 
    vector<int> a; 
    inputRoutine(a); 

    for (int COLS = 1; COLS < 6; ++COLS) // Here we loop over a few selected value of COLS 
    { 
     vector<int> row_sum; // To store the row sums 
     printRoutine(COLS, a, row_sum); 

     // The rest of the loop is just printing the row sums 
     std::cout << '\n' << COLS << '\t'; 
     for (int i : row_sum) 
     std::cout << i << ' '; 
     std::cout << std::endl << std::endl; 
    } 
}