C＃正则表达式，单引号之间的字符串

Question

string val = "name='40474740-1e40-47ce-aeba-ebd1eb1630c0'"; 

我想获得使用正则表达式的'引号之间的文本。

任何人都可以吗？

Answer 1

像这样的东西应该这样做：

string val = "name='40474740-1e40-47ce-aeba-ebd1eb1630c0'"; 

Match match = Regex.Match(val, @"'([^']*)"); 
if (match.Success) 
{ 
    string yourValue = match.Groups[1].Value; 
    Console.WriteLine(yourValue); 
} 

表达'([^']*)的说明：

' -> find a single quotation mark 
( -> start a matching group 
[^'] -> match any character that is not a single quotation mark 
* -> ...zero or more times 
) -> end the matching group 

Answer 2

您正在寻找匹配GUID在使用正则表达式的字符串。

这是你想要的，我怀疑！

public static Regex regex = new Regex(
    "(\\{{0,1}([0-9a-fA-F]){8}-([0-9a-fA-F]){4}-([0-9a-fA-F]){4}-"+ 
    "([0-9a-fA-F]){4}-([0-9a-fA-F]){12}\\}{0,1})",RegexOptions.CultureInvariant|RegexOptions.Compiled); 

Match m = regex.Match(lineData); 
if (m.Succes) 
{ 
... 
} 

Answer 3

这将提取第一和最后单引号之间的文本上一行：

string input = "name='40474740-1e40-47ce-aeba-ebd1eb1630c0'"; 
Regex regName = new Regex("'(.*)'"); 
Match match = regName.Match(input); 
if (match.Success) 
{ 
    string result = match.Groups[1].Value; 
    //do something with the result 
} 

Answer 4

你可以用积极的前瞻和回顾后也

string val = "name='40474740-1e40-47ce-aeba-ebd1eb1630c0'"; 

Match match = Regex.Match(val, @"(?<=')[^']*(?=')"); 
if (match.Success) 
{ 
    string yourValue = match.Groups[0].Value; 
    Console.WriteLine(yourValue); 
}