我在React Native中创建了一个应用程序,并且正在使用React Navigation。在主页面中,我有一系列的服务。我希望能够根据服务的索引路由到应用中的不同屏幕。这是代码的一部分。我怎么做?在React Native中使用React导航进行路由
import React, { Component } from 'react'
import {
StyleSheet,
Text,
TextInput,
View,
TouchableHighlight,
ActivityIndicator,
AppRegistry,
Image
} from 'react-native';
import { StackNavigator } from 'react-navigation';
import { addNavigationHelpers } from 'react-navigation';
import SelectMultiple from './SelectMultiple';
import PackingPage from './PackingPage';
const services =
['Packing Items in Boxes for Shipping and Moving',
'Unpacking Boxes',
'Wrap Furniture for Moving and Shipping',
'Wrap Machinery',
'Loading/Lumper Services',
'Unloading/Lumper Services',
'Custom Crating for Boxes, Furniture and Machinery',
'Palletizing Services for Boxes, Furniture and Machinery',
'Shipping/Moving Service to 2nd location',
'Heat Shrink wrapping',
'Shipping Food in AC trucks',
'Shipping Food in Non AC Truck',
'Shipping Cars']
class PackingApp extends Component{
static navigationOptions = {
title: '',
};
state = { selectedServices: [] }
onSelectionsChange = (selectedServices) => {
this.setState({ selectedServices })
}
到目前为止,我还有一个带有两个屏幕的堆栈导航器代码片段。我想为每个服务添加一个基于其索引的屏幕。我试过用if/else来做这件事,但我无法让它工作。
const PackingNav = StackNavigator({
Home: { screen: HomePage },
PackingPage: { screen: PackingPage },
},
{
headerMode: "none"
});
你的服务数组只是一个字符串数组。您需要为每个屏幕(或服务)创建一个组件,然后将其添加到StackNavigator,就像您为其他两个屏幕所做的一样。 –
是的,我为每个屏幕都有一个组件。每项服务应该对应一个屏幕。如何使用服务元素的索引来路由到其相应的屏幕? –