我遇到了一些使用getElementById的JavaScript问题。它可以在FF,Safari和Chrome中正常工作,但IE(8 - 没有尝试过其他)可以保留。Internet Explorer在getElementById上抛出错误
HTML的相关位是一个div叫topnav:
<div id="topnav">
... some HTML ...
<div>
<div id="sub_1" class="lowernav">
... some HTML ...
</div>
<div id="sub_2" class="lowernav">
... some HTML ...
</div>
在我的JavaScript,我想找到topnav。完整的代码(最多的地方捞出)是这样的:
<script>
window.onload = init();
function init() {
// Show current menu
showCurrentMenu();
}
function showCurrentMenu() {
hideMenus(); // Hide all menus and then show the current one
topnav = document.getElementById('topnav');
... rest of code ...
}
function hideMenus() {
var divlist = document.getElementsByTagName('div');
for(var ii=0; ii<divlist.length; ii++) {
if(divlist[ii].className != divlist[ii].className.replace('lowernav','')) {
divlist[ii].className += ' hidden';
}
}
}
...然后一些其他的代码还没有达到...
难道我做错了什么吗?这可能是一件非常明显的事情,但对我而言,我看不到它!所有的建议非常感谢。
ETA:好吧,这里是整个代码,因为它目前为:
<script>
window.onload = init;
function init() {
// Show current menu
showCurrentMenu;
// Attach 'onmouseover' event to main menu items
topnav = document.getElementById('topnav');
// Get all items in list
var menulist = topnav.getElementsByTagName('a');
for(var ii=0; ii<menulist.length; ii++) {
menulist[ii].onmouseover = showMenu;
}
document.getElementById('mainHomeNav').onmouseout = restoreMenu;
}
function restoreMenu(e) {
var targ;
if (!e) var e = window.event;
if (e.target) targ = e.target;
else if (e.srcElement) targ = e.srcElement;
if (targ.nodeType == 3) // defeat Safari bug
targ = targ.parentNode;
if (targ.id == "mainHomeNav") {
showCurrentMenu;
}
}
function hideMenus() {
var divlist = document.getElementsByTagName('div');
for(var ii=0; ii<divlist.length; ii++) {
if(divlist[ii].className != divlist[ii].className.replace('lowernav','')) {
divlist[ii].className += ' hidden';
}
}
}
function showCurrentMenu() {
hideMenus;
topnav = document.getElementById('topnav');
// Get all items in list
var menulist = topnav.getElementsByTagName('a');
for(var ii=0; ii<menulist.length; ii++) {
if(menulist[ii].className != menulist[ii].className.replace('thisSection','')) {
var thisid = menulist[ii].id;
var thissubmenu = document.getElementById(thisid + '_sub');
thissubmenu.className = thissubmenu.className.replace(/hidden/g,'');
}
}
}
function showMenu() {
hideMenus;
// show this menu
var submenu_id = this.id + '_sub';
var submenu = document.getElementById(submenu_id);
submenu.className = submenu.className.replace(/hidden/g,'');
}
</script>
+1为正确的答案。在尝试调试时容易犯错误,容易错过。 – Spudley 2011-01-14 15:47:10