PHP：$进去

Question

所以我想获取URL的一部分到一个PHP这是我的脚本

我想$_GET["m"]

<?php include('links.php'); ?> 
<?php echo $title ?> 

<?php include('links.php'); ?> 
<ul class="pageitem"><li class="textbox"><p> the codes go here</p></li></ul> 

Answer 1

德的Insidr代码在上真：

<?php include('links.php'); ?> 
<?php echo $title ?> 

<?php include('links.php'); ?> 
<ul class="pageitem"><li class="textbox"><p><?php echo $_GET["m"]; ?></p></li></ul> 

但你似乎有$title打印就好了。这是你在找什么？我不完全确定你在问什么。

Answer 2

$_GET是PHP中的Superglobal。你可以在任何地方使用它...

<?php include('links.php'); ?> 
<?php echo $title; ?> 

<?php include('links.php'); /* Is the double include intended? */ ?> 
<ul class="pageitem"> 
    <li class="textbox"> 
    <p> 
     I like a having my <?php echo $_GET['m']; ?> 
     in the morning. Who doesn't 
     like <?php echo $_GET['m']; ?> in the morning anyway? 
    </p> 
    </li> 
</ul>