-1
Members = ["MrRager", "Giancarlo", "TheFoolishOne"] # participants of Last Man Standing Challenge
MrRager = raw_input("Did Mr Rager make it through today?")
if MrRager == raw_input("No"):
Members.remove("MrRager")
print Members
# every time a member fails, doesn't check in for a while, or leaves we will remove from list above.
有麻烦所以,基本上我希望脚本要问的问题没有成员撑过今天。如果raw_input是yes,它将保持不变。然后,如果我输入“否”,我想要将该人从列表中移除。当我输入no时,再次打印它,然后保持列表相同。
'MrRager的raw_input ==(“否”):'??? =>'MrRager ==“否”:' –
您在''if'语句中写入'raw_input(..)',程序将再次查询... –
在旁注中,为什么我看到很多最近的C#风格的Python代码? :D Camelcase和东西... – bosnjak