2012-04-27 50 views
0

我试图将数据插入数据库,但是当我选择插入的内容时,我得到的数据不一致。Windows Phone中的SQLite客户端不一致的错误

等,我插入= “DATA1”,B = “DATA2”,C = “DATA3”

但是当我选择我获得= “0”,B = “DATA2”,C =”数据3"

为什么我用同样的方法,但其中一些得到不同的价值..

参考我实现:SQLiteClient for WP(我测试了它的代码运行正确,于是我跟着他究竟是怎么做到的,但然后我得到不同的结果..)

INSERT功能:

String t_title = txtTitle.Text; 
String t_img = "test"; 
String t_answer_a = txtAnswer1.Text; 
String t_answer_b = txtAnswer2.Text; 
String t_answer_c = txtAnswer3.Text; 
String t_answer_d = txtAnswer4.Text; 
String t_answer = txtAnswer1.Text; 
int t_cat = 1; 

int rec; 
Random rnd = new Random(); 
string strInsert = " INSERT INTO tlg_question (q_title,q_img,q_ques_a,q_ques_b,q_ques_c,q_ques_d,q_ans,q_cat) VALUES (@q_title,@q_img,@q_ques_a,@q_ques_b,@q_ques_c,@q_ques_d,@q_ans,@q_cat)"; 

tlg_question tst = new tlg_question 
{ 
    q_title = t_title, 
    q_img = t_img, 
    q_ques_a = t_answer_a, 
    q_ques_b = t_answer_b, 
    q_ques_c = t_answer_c, 
    q_ques_d = t_answer_d, 
    q_ans = t_answer, 
    q_cat = t_cat 
}; 
rec = (Application.Current as App).db.Insert<tlg_question>(tst, strInsert); 

选择功能:

ObservableCollection<tlg_question> _tlg_questionEntries = null; 

string strSelect = "SELECT q_id,q_title,q_img,q_ques_a,q_ques_b,q_ques_c,q_ques_d,q_ans,q_cat FROM tlg_question ORDER BY q_id DESC LIMIT 0,1"; 
_tlg_questionEntries = (Application.Current as App).db.SelectObservableCollection<tlg_question>(strSelect); 

foreach (tlg_question data in _tlg_questionEntries) 
{ 
    qid = data.q_id; 
    txtTitle.Text += data.q_title; 
    img = data.q_img; 
    txtAnswer1.Text += data.q_ques_a; 
    txtAnswer2.Text += data.q_ques_b; 
    txtAnswer3.Text += data.q_ques_c; 
    txtAnswer4.Text += data.q_ques_d; 
} 

而且我的更新功能:

String t_title = txtTitle.Text; 
String t_answer_a = txtAnswer1.Text; 
String t_answer_b = txtAnswer2.Text; 
String t_answer_c = txtAnswer3.Text; 
String t_answer_d = txtAnswer4.Text; 

int rec; 
Random rnd = new Random(); 
string strUpdate = " UPDATE tlg_question SET [email protected]_title,[email protected]_ques_a,[email protected]_ques_b,[email protected]_ques_c,[email protected]_ques_d,[email protected]_ans WHERE [email protected]_id"; 

tlg_question tst = new tlg_question 
{ 
    q_id = qid, 
    q_title = t_title, 
    q_ques_a = t_answer_a, 
    q_ques_b = t_answer_b, 
    q_ques_c = t_answer_c, 
    q_ques_d = t_answer_d, 
    q_ans = t_answer_a 
}; 
rec = (Application.Current as App).db.Update<tlg_question>(tst, strUpdate); 

欣赏人谁可以帮我!

*或者,如果你认为我应该放弃SQLite和去其他数据库,请让我知道,我在挑首位SQLite的,因为它处理,如MySQL简单的查询,以及FF SQLite的经理..

谢谢!

回答

0

好吧,我已经测试过,最后发现,我需要同时插入或更新所有列,然后只有我可以正确完成工作,我不确定这是因为DBHelper限制发生的还是来自SQLiteClient。

进一步了解详细:

例如,如果我的预置数据库宣布4列如下:

[q_id, q_title, q_ques, q_ans] (q_id as Auto Increment) 

然后当我在做INSERT或UPDATE,甚至我只需要插入只有q_title(而离开q_ques和q_ans使用默认值),我将需要包括所有列的运行参数:

INSERT INTO tlg_question (q_title,q_ques,q_ans) VALUES (@q_title,@q_ques,@q_ans)"; 

不喜欢我做的,通常在PHP MYSQL,我可以简单地插入/更新特定的专栏中,我想没有问题:

INSERT INTO tlg_question (q_title) VALUES (@q_title)"; 

P/S:我在SQLite和C#新的,请指教/纠正我,如果你知道什么是实际发生的事情..

谢谢! :)