我已经写了一些代码来检索zip文件并将其解压缩为directoy。该zip文件包含两个文件夹,并根据每个文件所在的文件夹,将其解压缩到该目录的文件夹中。解压缩文件真的很慢
但是,代码需要很长的时间才能运行(大约10分钟)。尽管这些文件夹每个包含近1000个文件,并且zip文件的总大小为5000kb。我觉得它很慢,因为我每次进入循环时都会创建FileOutputStream和InputStream。但是,我需要这样做,因为我不知道文件的输出目录,直到我从zip文件中读取它为止。 (即找出它在哪个文件夹)
有什么建议吗?
/**
* Retrieves and unzips a file from its URL
*/
public void retrieveFiles(String URL) {
//Retrieve file from URL
File zip = new File(getFile(URL));
zip.mkdirs();
try {
//Create .zip file from file directory
ZipFile zipFile = new ZipFile(zip);
Enumeration<? extends ZipEntry> enumeration = zipFile.entries();
//While zip file contains elements, get the next zipped file
while (enumeration.hasMoreElements()) {
ZipEntry zipEntry = (ZipEntry) enumeration.nextElement();
//Ignore folders and other zip files
if(!zipEntry.isDirectory() && !zipEntry.getName().endsWith(".zip")){
//Find directory and filename for new unzipped file
String directory = getURL(zipEntry.getName());
String fileName = getFileName(zipEntry.getName());
String fullDirectory = createDirectory(directory, fileName);
//Unzip file and store in directory
System.out.println("Unzipping file: " + fileName);
FileOutputStream fout = new FileOutputStream(fullDirectory);
InputStream in = zipFile.getInputStream(zipEntry);
for (int c = in.read(); c != -1; c = in.read()) {
fout.write(c);
}
zipFile.getInputStream(zipEntry).close();
in.close();
fout.close();
}
}
zipFile.close();
System.out.println("Unzipping complete!");
zip.delete();
} catch (IOException e) {
System.out.println("Unzip failed");
e.printStackTrace();
}
}
你不妨考虑一下http://codereview.stackexchange.com/ –
另见:[java.util.zip - 重新创建目录结构](http:// stackoverflow .com/questions/1399126) – McDowell