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我想通过使用Scala和Play 2.4.6的多部分表单数据发送文件。如何发送Scala FilePart [TemporaryFile]作为Java文件?
def sendFile(file: FilePart[TemporaryFile]): Option[Future[Unit]] = {
val asyncHttpClient:AsyncHttpClient = WS.client.underlying
val postBuilder = asyncHttpClient.preparePost(s"${config.ocrProvider.host}")
val multiPartPost = postBuilder
.addBodyPart(new StringPart("access_token",s"${config.ocrProvider.accessToken}"))
.addBodyPart(new StringPart("typename",s"${config.ocrProvider.typeName}"))
.addBodyPart(new StringPart("action",s"${config.ocrProvider.actionUpload}"))
.addBodyPart(new FilePart(???)
}
我是新的Scala和Play,我想发送文件方法属性作为新的FilePart。可能吗?