我有一个kendo Treeview,它显示父节点但没有看到子节点。谁能告诉我我哪里错了。我对这个概念很陌生。我跟着下面的链接,但它不工作。 http://demos.telerik.com/kendo-ui/treeview/remote-data-bindingKendo treeview HierarchicalDataSource不显示子节点
function treeView() {
var treeM = new kendo.data.HierarchicalDataSource({
schema: {
data: function (response) {
console.log("response" + JSON.stringify(response));
var rdata = {};
if (response.d) {
rdata = JSON.parse(response.d);
}
else {
rdata = response;
}
return rdata; // ASMX services return JSON in the following format { "d": <result> }.
},
model: {
hasChildren: true,
id: "ID",
expanded: true,
fields: {
ID: { editable: false, nullable: false, type: "string" },
LINK: { editable: true, nullable: true, type: "string" },
},
},
},
transport: {
read: {
url: "/getParent",
contentType: "application/json; charset=utf-8",
type: "POST",
datatype: "json"
},
parameterMap: function (data, type) {
if ((type == "update") || (type == "create") || (type == "destroy")) {
console.log('parameterMap:');
return JSON.stringify({ "LinksJson": data });
console.log(JSON.stringify(data));
} else {
return data;
}
}
}
});
$("#treeview1").kendoTreeView({
dataSource: treeM,
dataValueField: "ID",
dataTextField: ["LINK","Name"]
});
}
$("#treeview").on("click", ".k-in", function (e) {
var tree = $("#treeview").data('kendoTreeView');
tree.toggle($(e.target).closest(".k-item"));
});
$(document).ready(function() {
treeView();
});
服务:
[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
public string getParent()
{
using (var context = new Data.Entities())
{
IQueryable<ERPv2.Data.Links> dataQuery = from x in context.Links
where x.ParentID == 68
select x;
var newQry = dataQuery.AsEnumerable().Select(c => new
{
ID = c.ID,
Name = c.Name,
Children = HasChildren(231)
});
JavaScriptSerializer JSON = new JavaScriptSerializer();
return JSON.Serialize(newQry);
}
}
[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
public bool HasChildren(int ID)
{
using (var context = new Data.Entities())
{
IQueryable<ERPv2.Data.Links> dataQuery = from x in contextLinks
where x.ParentID == ID
select x;
return dataQuery.AsEnumerable().Any();
}
}
感谢您的建议我一直在尝试你从1天说,但不知何故我无法写出查询。我已经添加了LINQ查询可以请检查它并建议我并更新代码 – Nethra