刷新随机在一个if case

Question

我生成两个随机的int数（a和b）。如果（a％b）== 0，我想继续，否则我想通过刷新来更改随机数。我举个例子的代码：

int a = //random; 
int b = //random; 
if ((a%b)==0) { 
    // do something 
} else { 
    // I want to change a and b and do that if case again. 
} 

Answer 1

int a= // random 
int b= // random 
while ((a%b)!=0) 
{ a = // random; 
    b = // random; 
} 
// a and b are random and out of the loop which means (a%b)==0 
// do something with a and b 

Answer 2

int a = //random; 
int b = //random; 
while((a%b)!=0) { 
    a = // random 
    b = // random 
} 
// do something 

所以在这种方式中，当A％B不等于0时，就会产生新的随机a和b 当while循环的条件为假它会停止产生这个，然后你可以恢复你的代码